Ask question

Ask question

All categories

3 years ago

13

What are the x-intercept and y-intercept of the graph of y=−12x+4y=−12x+4 ?

1 answer:

miskamm [114]3 years ago

6 0

The x-intercept is the value of x when y is equal is zero. It is the point in the x-axis intersected by the line. The y-intercept is the value of y when x is zero. It is where the line intersects in the axis. Therefore, for the given equation:

<span>y=−12x+4

</span><span>y=−12(0)+4 = 4<--------y-intercept

</span><span>0=−12x+4
x = 1/3 <--------x-intercept</span>

You might be interested in

Write the ratios for sin X, cos X, and tan X. Use the / for a fraction.

fgiga [73]

Answer:

Step-by-step explanation:

From the right triangle attached in the picture,

sine ratio for the angle X,

$\text{sinX}=\frac{\text{Opposite side}}{\text{Hypotenuse}}$

$=\frac{YZ}{XZ}$

$=\frac{21}{29}$

cosine ratio for the angle X,

$\text{cosX}=\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

$=\frac{XY}{XZ}$

$=\frac{20}{29}$

tang ratio for the angle X,

$\text{tanX}=\frac{\text{Opposite side}}{\text{Adjacent side}}$

$=\frac{21}{20}$

3 0

3 years ago

The temperature is -3°F at 7:00 A.M. During the next 4 hours, the temperature increases 21°F. What is the temperature at 11:00 A

3241004551 [841]

Answer: 18°F

Step-by-step explanation: if you add 21 and -3 you get 18

4 0

3 years ago

I WILL MARK BRAINLIEST!!!!!!!!!

Lubov Fominskaja [6]

Answer:

It is not

Step-by-step explanation:

It is not because this is an exponential function

y=x^2

1^2=1

2^2=4

3^2=9

4^2=16

7 0

3 years ago

Dominick's puppy weighs 8 pounds and is gaining about 1 3/4 pounds each week, what's the rate of change

N76 [4]

Your rate of change would be 3/4 lb/week.
You could model this with a linear eq:

y = 8+ 3/4x

5 0

4 years ago

Anything helps ! Brainilest to right answer only .!

Alex_Xolod [135]

x = -16 or x = 5

Solution:

Given polynomial:

$x^{2}+11 x-80=0$

To find the roots of the polynomial.

Split the middle term 11x.

11x = 16x - 5x

$x^{2}+11 x-80=0$

$x^{2}+16x-5x-80=0$

$(x^{2}+16x)+(-5x-80)=0$

Take the x common in first 2 terms an -5 common in next 2 terms.

$x(x+16)-5(x+16)=0$

Take (x + 16) common in both terms.

$(x+16)(x-5)=0$

x + 16 = 0 or x - 5 = 0

x = -16 or x = 5

Hence x = -16 or x = 5.

6 0

3 years ago