Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
As x = 5 & z=12,
<span>2/3 = y /(xz) = y/(5*12) </span>
<span>= y/60 </span>
<span>so y / 60 = 2/3 </span>
<span>y = (2*60)/3 </span>
<span>= 40</span>
Answer:
x = 4.9 cm
Step-by-step explanation:
Note that sin theta = (opp side) / (hypotenuse), and that:
hypotenuse (opp side)
------------------ = -----------------
1 sin theta
and so:
hypotenuse (opp side) 4 cm
------------------ = ----------------- or hypotenuse = ---------------------------- = x
1 sin theta sin (55 degrees)
4 cm
Thus, x = --------------- = x = 4.88 cm or (to 1 DP) x = 4.9 cm
0.819
Answer:
2 is the number of dollars per seed.
6 is the number of lettuce seeds bought.
7 is the number of pea seeds bought.
word expression: two dollars multiplied by six plus seven packets of seeds.
