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4 years ago

Sphere A has a radius of 24 centimeters, and sphere B has a diameter of 42 centimeters. The radius of sphere A is multiplied

Mathematics

1 answer:

Eddi Din [679]4 years ago

7 0

Answer:

1.75

Step-by-step explanation:

The radius of Sphere A = 24 centimeters

The radius of sphere B = 42 centimeters

$\text{Radius of Sphere B} \div \text{Radius of Sphere A}=42 \div 24\\=1.75$

Therefore, The radius of sphere A is multiplied by 1.75 to produce the radius of sphere B

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Identify this sequence: 5, 15, 45, 135, …<br> Arithmetic<br> Geometric<br> Neither

user100 [1]

Answer:

5 * 2 is 10 + 5 and then 15 * 2 + 15 45 * 2 + 45

Step-by-step explanation:

times it by to add that number

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3 years ago

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Renee has a total of 12 cookies in chocolate chip and peanut butter, C + P = 12. The number of chocolate chip cookies is three t

Reika [66]

Answer:

Renee has 9 Chocolate chip cookies and 3 peanut butter cookies.

Step-by-step explanation:

This is a system of equations:

C + p = 12

C = 3P

All you need to do is substitute C for 3P in the first equation.

C + P = 12

3P + P = 12

4P = 12

Divide both sides by 4

4P/4 = 12/4

P = 12/4

P = 3

Now, substitute P for 3 in the first equation.

C + P = 12

C + 3 = 12

Subtract 3 from both sides

C + 3 - 3 = 12 - 3

C = 12 - 3

C = 9

C = 9, P = 3

7 0

3 years ago

Read 2 more answers

Suppose that the population density of a certain area is 80 people per square mile. If about 440,000 people live in this area, w

Zina [86]

The answer is B) 5,500 mi^2

6 0

3 years ago

SOLVE FOR X <br> x/2/5 =10/11 .

finlep [7]

5x/2 = 10/11
55x = 20
x = 4/11
**Not sure if I did this right I think I did

8 0

3 years ago

a rectangle is 8cm longer then it is wide, and it’s area is 153cm^2. Find the dimensions of the rectangle.

Stolb23 [73]

Answer:

Width of 9cm and length of 17cm.

Step-by-step explanation:

To calculate an area of a rectangle, use the formula A=l*w. We know the length is 8cm longer than the width. So l = 8 + w. So the area is A= (8+w)*w.

We also know the area is 153. Substitute this value for A and solve.

$153 = (8+w)(w)\\153 = 8w+w^2\\w^2+8w-153 = 0$

To solve the quadratic, use the quadratic formula:

$\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

Here a=1, b=8 and c=-153.

$w=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\w=\frac{-8+/-\sqrt{8^2-4(1)(-153)} }{2(1)} \\w=\frac{-8+/-\sqrt{64+612} }{2} \\w=\frac{-8+/-\sqrt{676} }{2} \\w=\frac{-8+/-26 }{2} \\w=\frac{-8+26 }{2}=\frac{18}{2}=9 \\and\\w=\frac{-8-26 }{2} =\frac{-34}{2}=-17$

Since w=9 or w=-17, substitute this value for w in l= 8+w to find l.

l = 8+9 = 17

l=8+-17 = -9

Since length cannot be positive, it must be l=17 and w=9.

8 0

3 years ago