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3 years ago

How do I quit this and get this 7 day offer off of my credit card?

Mathematics

1 answer:

victus00 [196]3 years ago

5 0

Answer:

Cancel the credit card

Step-by-step explanation:

If you don't have the card, it can't be charged to you

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Fill in the blank (correctly). 20 points each.

lyudmila [28]

Distributing same key numbers

7 0

3 years ago

angle A is a compliment of angle b and m angle b = (6-5x) degrees and m angle a =(7-2x)degrees find m angle a

Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

A + B = 90

6 - 5x + 7 - 2x = 90

13 - 7x = 90

- 7x = 90 - 13

- 7x = 77

- x = 77 / 7

x = - 11

A: 6 - (5 * - 11) = 6 + 55 = 61

B: 7 - (2 * -11) = 7 + 22 = 29

Together they equal 90 as they should.

7 0

3 years ago

Clue 1

nikklg [1K]

The number is 112
1. Three digits
2. Less than 140
3. 7 is a factor
4. Even
5. 1+1+2 = 4

7 0

1 year ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

2 years ago

In this picture, m∠PQR = 161° and m∠SQR = 38°. If m∠PQS = (2x + 15)°, what is the value of x?

elena55 [62]

Answer:

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers