Recall that
and
for all
. So


For
, we expect both
and
(i.e. the sine and cosine of any angle that lies in the first quadrant must be positive). By definition of absolute value,
if
.
So we have

making H the answer.
C is always true, because the inequality reduces to x > y.
Answer:
It's going to be B and E because it's in the hundreds place not in the tens or whole
Its C cause the y intercept is -5
Answer:
Yes, as long as it is terminating, or ending and does not repeat forever.