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Umnica [9.8K]
3 years ago
15

The graph shows the costs of two types of fruit at a store.

Mathematics
1 answer:
Anna71 [15]3 years ago
6 0
You can see the slope of the line for cost per pound of cherries is greater, or in other words the line is more steep and traveling higher faster. Therefore, we know that the cost per pound of cherries is greater than that of apples because the cost increases more with each pound.

Hope this helps : )
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A regular six sided die and an eight equal segment spinner, numbered 1 to 8, are rolled/spun simultaneously. What are the odds i
kirill [66]

Answer:

1/3

Step-by-step explanation:

In statistics, the probability of both an event A and an event B happening is equal to the probability of A happening multiplied by the probability of event B happening.

Let's say spinning a prime number is event A and rolling a number ≤ 4 is event B.

There are 8 possibilities on an eight equal segment spinner, and there are 4 prime numbers between 1 and 8 (including 8), which are 2, 3, 5, and 7. This means that the probability of spinning a prime number is 4/8, or 1/2

There are 6 possibilities on a die, and there are 4 possibilities of rolling a 4 or less (1, 2, 3, 4). Therefore, the probability of rolling 4 or less on a die is 4/6, or 2/3

The probability of both of these happening can be calculated by multiplying these together, so 1/2 * 2/3 = 2/6 = 1/3

8 0
2 years ago
Section J in an arena has 20 rows each row has 15 seats all tickets cost $18 each people if all the seats are sold how much mone
Novosadov [1.4K]
First do 20×15, then the answer multiply by 18.
5 0
3 years ago
Read 2 more answers
Trey’s car has a 20-gallon fuel tank. The fuel gauge points to ¼ . If Trey buys 10 gallons of gas, what will be the new reading
Lelu [443]

Answer:

3/4

Step-by-step explanation:

1/4 + 2/4 = 3/4


5 + 10 = 15

6 0
3 years ago
Read 2 more answers
Could someone help me, please?
k0ka [10]

We can rewrite the expression under the radical as

\dfrac{81}{16}a^8b^{12}c^{16}=\left(\dfrac32a^2b^3c^4\right)^4

then taking the fourth root, we get

\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|

Why the absolute value? It's for the same reason that

\sqrt{x^2}=|x|

since both (-x)^2 and x^2 return the same number x^2, and |x| captures both possibilities. From here, we have

\left|\dfrac32a^2b^3c^4\right|=\left|\dfrac32\right|\left|a^2\right|\left|b^3\right|\left|c^4\right|

The absolute values disappear on all but the b term because all of \dfrac32, a^2 and c^4 are positive, while b^3 could potentially be negative. So we end up with

\dfrac32a^2\left|b^3\right|c^4=\dfrac32a^2|b|^3c^4

3 0
3 years ago
PLEASE HELP ASAP!!
andriy [413]
If I did this correctly it simplifies to 0 = 8. So I think B is the correct answer. Hope this helps!!
6 0
3 years ago
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