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Whitepunk [10]
3 years ago
11

M(-5, 2) and N(5, 2) are the endpoints of the segment MN on the coordinate plane. What is the length of ?

Mathematics
2 answers:
JulijaS [17]3 years ago
7 0

ccccccccccccccccccc

cccccc

VikaD [51]3 years ago
6 0
The line segment is 10 units long
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Which equation represents the line that passes through points (1 -5) and (3 -17)
Fynjy0 [20]

Answer:

6x-11

Step-by-step explanation:

m=<u>y2-y1</u>

x2-x1

<u>-</u><u>1</u><u>7</u><u>-</u><u>-</u><u>5</u> = <u>-</u><u>1</u><u>2</u>

3-1. -2

The two negatives cancel ❌

m=<u>1</u><u>2</u>

2

Divide by 2

m=6

y=mx+b

-5= 6 (1) + b

-5= 6 + b

Subtract (6) from both sides

b= -11

The equation for the line is 6x -11

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What is the solution to the rational equation x over 2x plus 1 minus 1 over 4 equals 2 over 2x plus 1
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X 1 2 ----- + ---- = ------- so the common denominator will be 4(2x-1) 2x-1 4 2x -1 4x +2x-1 8 ----------- = --------- 4(2x-1) 4(2x-1) 6x-1 8 ---------- = -------- make the restriction for x so 2x-1 =0 ,result x=1/2 4(2x-1) 4(2x-1) so what mean that x not can being equal 1/2 6x-1=8 6x = 9 x= 9/6 x = 3/2
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3 years ago
F(x) = x2 – 3x – 2 is shifted 4 units left. The result is g(x). What is g(x)?
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\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\\\&#10;&#10;\begin{array}{rllll} &#10;% left side templates&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\end{array}

\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}&#10;\\\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\end{array}

\bf \begin{array}{llll}&#10;&#10;&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}&#10;\end{array}

now... your expression is not in vertex form, that's ok... to do a horizontal shift to the left by 4 units, we can simply, add the C  and B component to the "x" variable, C=4, B =1, that way the horizontal shift of C/B or 4/1 is just +4, giving us a horizontal shift to the left

\bf f(x)=x^2-3x-2\impliedby \textit{let's change that for }f(1x+4)&#10;\\\\\\&#10;f(1x+4)=(1x+4)^2-3(1x+4)-2&#10;\\\\\\&#10;f(x+4)=x^2+8x+16-3x-12-2&#10;\\\\\\&#10;f(x+4)=x^2-5x+2\impliedby g(x)


8 0
3 years ago
Read 2 more answers
The value of the expression 23 +32–3x4–52-5+(7x4) is
Mashcka [7]

Answer:

24

Explanation:

(23+32)-(3×4)-(52-5)+(7×4)

(55)-(12)-(47)+(28)

  • 55-12=43
  • -47+28= -19
  • 43-19=24
4 0
3 years ago
Write an equation in slope intercept form (y=mx+b) for the graph below .
jolli1 [7]

Answer:

Step-by-step explanation:

b would be 0

your slope is rise/run. up one and over three. up one and over three. so 1/3

write it as y=1/3x+0, or y=1/3x

6 0
3 years ago
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