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ANEK [815]
4 years ago
8

Help would be nice‍♀️.

Mathematics
2 answers:
11111nata11111 [884]4 years ago
5 0

Answer:

the ones with a line above the numbers are repeating decimals

Genrish500 [490]4 years ago
4 0

Answer:

#4

Step-by-step explanation:

The symbol for repeating decimals is a line over the last number in the decimal :)

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Why is adding 3/9 and 6/9 different from multpying the two fractions? Explain
tankabanditka [31]
<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ When you add fractions, you have to have the same denominator whereas, when you multiply them, you don't have to. (In this case the denominators are already the same.) Also, multiplying the fractions would make the result smaller whereas adding them would make it larger.

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4 0
4 years ago
Can someone help with this
kari74 [83]

Answer:

I think D option is write hope you help

5 0
3 years ago
A store has a 20% off sale on pants. With this discount, the price of one pair of pants before tax is $15.20.
algol13

Answer:

19$

Step-by-step explanation:

Because 19$ 20% off=15.20 and you added taxes]

Have a great day :}

5 0
3 years ago
Read 2 more answers
Express the terms of the following geometric sequence recursively.
BabaBlast [244]

Answer:

The most correct option for the recursive expression of the geometric sequence is;

4. t₁ = 7 and tₙ = 2·tₙ₋₁, for n > 2

Step-by-step explanation:

The general form for the nth term of a geometric sequence, aₙ is given as follows;

aₙ = a₁·r⁽ⁿ⁻¹⁾

Where;

a₁ = The first term

r = The common ratio

n = The number of terms

The given geometric sequence is 7, 14, 28, 56, 112

The common ratio, r = 14/7 = 25/14 = 56/58 = 112/56 = 2

r = 2

Let, 't₁', represent the first term of the geometric sequence

Therefore, the nth term of the geometric sequence is presented as follows;

tₙ = t₁·r⁽ⁿ⁻¹⁾ = t₁·2⁽ⁿ⁻¹⁾

tₙ =  t₁·2⁽ⁿ⁻¹⁾ = 2·t₁2⁽ⁿ⁻²⁾ = 2·tₙ₋₁

∴ tₙ = 2·tₙ₋₁, for n ≥ 2

Therefore, we have;

t₁ = 7 and tₙ = 2·tₙ₋₁, for n ≥ 2.

4 0
3 years ago
Pablo uses 4 centimeters of tape for every present he wraps . How much tape will Pablo need in all if he has to wrap 9 presents?
OLga [1]

Answer:

36 centimeters of tape

Step-by-step explanation:

6 0
3 years ago
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