Answer:
18. compound interest
19. simple interest
20. simple interest
Step-by-step explanation:
For these problems, the initial balance is irrelevant. All that matters is the multiplier of that balance. For simple interest at rate r for t years, the multiplier is ...
simple interest multiplier = (1 +rt)
For interest compounded annually, the multiplier of the initial balance is ...
compound interest multiplier = (1 +r)^t
A spreadsheet can do the computations for you.
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As an example of the computations involved, consider problem 19:
simple interest multiplier = 1 + 0.13·6 = 1.78
compound interest multiplier = 1.10^6 = 1.771561
The latter is less than the former, so the simple interest account will have the (slightly) greater balance at the end of 6 years.
Answer:
Midpoint Formula= (x1+x2)/2, (y1+y2)/2
Plug in the numbers
Answer= (0, 0)
I hope this helps you!!
The function is
![h(t) = -16t^2 + 80t + 224](https://tex.z-dn.net/?f=h%28t%29%20%3D%20-16t%5E2%20%2B%2080t%20%2B%20224)
, and according to the description of the function in the problem statement, we have the following:
at t=0 after being thrown (that is, at initial time), the height of the ball is calculated by h(0) as follows:
![h(0) = -16(0)^2 + 80(0) + 224=0+0+224=224](https://tex.z-dn.net/?f=h%280%29%20%3D%20-16%280%29%5E2%20%2B%2080%280%29%20%2B%20224%3D0%2B0%2B224%3D224)
(ft), which is the initial height, as expected.
At t=1 (sec), the height would be
![h(1) = -16(1)^2 + 80(1) + 224=-16+80+224=288](https://tex.z-dn.net/?f=h%281%29%20%3D%20-16%281%29%5E2%20%2B%2080%281%29%20%2B%20224%3D-16%2B80%2B224%3D288)
.
etc.
The path is parabolic, as we know by seeing that the function is a quadratic polynomial function. This function has been given in factored form as well. From that we can see that the zeros of the function are t=7 and t=-2.
This means that at t=7 sec, the height h is 0, which means that the ball has hit the ground. t=-2 has no significance in the context of our problem so we just neglect it.
Answer: B) 7 sec