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alisha [4.7K]
3 years ago
7

How far will a skier travel in 2 1/2 minutes? Explain how you figured it out

Mathematics
1 answer:
Kay [80]3 years ago
8 0

3600 meters 60 seconds would be 1440 traveled

and 1440 + 1440 + 720= <u>3600</u>

Hope this helps :)

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Don’t mind the Answer D I circle can someone explain the answer to me 25 point if no explanation and answer I flagged
Kruka [31]

Answer:

 (A) 49

Explanation:

Given that the fractions are in their simplest form. So below the denominator cannot be a multiple of 3, 4, 5.

Breakdown:

Looking at option A (49), it is not a multiple of 3, 4, 5. So k can be 49.

Option B (50) is a multiple of 5. An even number like 4 so can be simplified.

Option C (51) is a multiple of 3 so can be simplified more. 3/51 = 1/17.

Option D (52) is an even number like 4 so can be simplified. 4/52 = 1/13.

4 0
2 years ago
[GEOMETRY] Suppose A and B are independent events.  what is P(A U B) ?
ra1l [238]
My guess would be B.
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8 0
3 years ago
explain why in a drawer only containing two different colors of socks one must pull 3 out to find a matching pair?
Lorico [155]
If there are only two colors (let's say blue and red), here's what can happen:
sock #1 is blue
#2 is either blue or red. If blue, it matches #1 and you have a pair.
if red, go to #3
#3-either blue or red. If blue, matches #1. If red, matches #2.

OR sock #1 is red... then just reverse the colors. Basically, if you have three things that can only be in two groups, then even if two of them are different, the last one has to match one of them.

8 0
3 years ago
Are these answers right?
Alla [95]

Answer:

Yes, good job! :)

4 0
3 years ago
Which term of ap 30,27,24is0
son4ous [18]

Answer:

11th term is 0

Step-by-step explanation:

30, 27 , 24 ,......0

a = first term = 30

Common difference = second term - first term = 27 - 30 = -3

nth term = a+(n-1)*d

a + (n-1)d = 0

30 + (n - 1) *(-3) = 0

30 + n*(-3) -1*(-3) = 0

30 - 3n + 3 = 0

      -3n + 33 = 0

               -3n = -33

                   n = -33/-3

n = 11

8 0
3 years ago
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