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Tanya [424]
3 years ago
10

A diver is at an elevation of -18 feet relative to sea level. The diver descended to an undersea cave that is 4 times as far fro

m the surface.What is the elevation of the cave?
Mathematics
1 answer:
VLD [36.1K]3 years ago
8 0

Answer:

  -72 feet

Step-by-step explanation:

Four times -18 feet is ...

  4(-18) = -72

The elevation of the cave is -72 feet.

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Help I don’t understand a little confusing
Alexandra [31]

Answer:

40

Step-by-step explanation:

1. 2(l+w)

2. 2(17+3)

3. 2(20)

4. 2*20

4 0
3 years ago
If the two angles below are supplementary, solve for x.
IrinaVladis [17]
Supplementary angles always equal 180. Then you just solve from there.

7x+5x+24=180
12x+24=180
-24 -24
12x=156
/12 /12
X=12
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What is 3/2 divide by 1/4
Dovator [93]

Answer:

6

Step-by-step explanation:

Yw :)

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3 years ago
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The boxed definition of absolute value states that |a|=-a if a is a negative number. Explain why |a| is always nonnegative, even
Temka [501]

Final answer:

Since absolute values determine the distance between the number and the value whether the value is positive or negative. As distance is always positive.

Thus, |a| is always nonnegative, even though |a|=-a for negative values of a.

Step-by-step explanation:

Step 1

It is said that |a| is always nonnegative even though even though |a|=-a for negative values of a.

Step 2

This is because by the definition of an absolute value, any real number inside an absolute value symbol || will always be positive.

7 0
2 years ago
Which of the following operations is true regarding relative frequency distributions? Multiple choice question. No two classes c
pshichka [43]

Answer:

The relative frequency is found by dividing the class frequencies by the total number of observations

Step-by-step explanation:

Relative frequency measures how often a value appears relative to the sum of the total values.

An example of how relative frequency is calculated

Here are the scores and frequency of students in a maths test

Scores (classes)              Frequency                Relative frequency

0 - 20                                10                               10 / 50 = 0.2

21 - 40                               15                               15 / 50 = 0.3

41 - 60                               10                               10 / 50 = 0.2

61 - 80                                5                                 5 / 50  = 0.1

81 - 100                             <u> 10</u>                                10 / 50 = <u>0.2</u>

                                          50                                               1

From the above example, it can be seen that :

  1. two or more classes  can have the same relative frequency
  2. The relative frequency is found by dividing the class frequencies by the total number of observations.
  3. The sum of the relative frequencies must be equal to one
  4. The sum of the frequencies and not the relative frequencies is equal to the number of observations.

4 0
3 years ago
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