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qaws [65]
3 years ago
5

The equation of a line is x+4y=15

Mathematics
2 answers:
Pani-rosa [81]3 years ago
8 0
The y-intercept of the line is the value of "y" when x=0
Therefore:
if x=0
0+4y=15
4y=15
y=15/4

Answer: A.  15/4
Monica [59]3 years ago
8 0

To find the y intercept of the line we need to know x=0

x+4y=15 The original problem.

x(0)+4y=15 X=0

4y=15   Simplified

x=3.75 or 15/4  Divide by both sides

Easy answer: A

There's your answer! Hope it helps

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(18x-44 )(8x-10) (13y-38) geometry
xenn [34]

Simplifying

18x + -44 = 13y + -38

Reorder the terms:

-44 + 18x = 13y + -38

Reorder the terms:

-44 + 18x = -38 + 13y

Solving

-44 + 18x = -38 + 13y

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '44' to each side of the equation.

-44 + 44 + 18x = -38 + 44 + 13y

Combine like terms: -44 + 44 = 0

0 + 18x = -38 + 44 + 13y

18x = -38 + 44 + 13y

Combine like terms: -38 + 44 = 6

18x = 6 + 13y

Divide each side by '18'.

x = 0.3333333333 + 0.7222222222y

Simplifying

x = 0.3333333333 + 0.7222222222y

3 0
3 years ago
Identify the stem: 556 <br> A. 5<br> B. 6<br> C. 55<br> D. 56<br> ...Ahem.. Help?
Semenov [28]
C. a leaf is only one digit
3 0
3 years ago
Read 2 more answers
El Club de Matemáticas está horneando pasteles para una venta de
SVETLANKA909090 [29]

Answer:

56

Step-by-step explanation:

El problema se puede transcribir en esta ecuación:

2x + x = 168

siendo x las nectarinas

sumas los términos de x:

3x=168

despejas x:

x = 168 ÷ 3

x = 56

5 0
3 years ago
How do u do b??????????
horrorfan [7]

the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.

the input goes to the 1st machine and the output of that goes to the 2nd machine.

a)

if she uses and input of 6 on the 2nd one, the result will be 6² - 6  = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.

b)

clearly we can never get an output  of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.

let's check something, we need a -5 on the 2nd, so

\bf \underset{final~out put}{\stackrel{y}{-5}}=x^2-6\implies 1=x^2\implies \sqrt{1}=x\implies 1=x

so if we use a "1" as the output on the first machine, we should be able to find out what input we need, let's do that.

\bf \underset{first~out put}{\stackrel{y}{1}}=\sqrt{x-5}\implies 1^2=x-5\implies 1=x-5\implies 6=x

so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.

\bf \stackrel{first~machine}{y=\sqrt{\boxed{6}-5}}\implies y=\sqrt{1}\implies y=1 \\\\\\ \stackrel{second~machine}{y = \boxed{1}^2-6}\implies y = 1-6\implies y = -5

5 0
3 years ago
Find the sum of all the prime numbers between 20 and 40.
Helga [31]

Answer:

120

Step-by-step explanation:

yw dude

3 0
3 years ago
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