You paid ..I’m broke so I can’t lol ..in my opinion it can be helpful sometimes because some of the questions don’t get answered or it’s someone just saying “I don’t know

7 0

2 years ago

How can i find the área of a triangle? please help.

Anni [7]

This is the area of a triangle

7 0

3 years ago

Read 2 more answers

What is the interquartile range of this data set?<br> 2,5,9,11,18, 30, 42, 48, 55, 73, 81

Lubov Fominskaja [6]

Answer:

Step-by-step explanation:

55-9=46

2=min

9=Lq

30=median

55= Uq

81= max

3 0

3 years ago

From first principles, find the indicated derivatives

LenaWriter [7]

By definition of the derivative,

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{(s + h)^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{s^3+3s^2h+3sh^2+h^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\frac{3s^2h+3sh^2+h^3}2}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 \frac{3s^2h+3sh^2+h^3}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 (3s^2+3sh+h^2)$

$\displaystyle\frac{dr}{ds} = \frac{3s^2}2$

6 0

2 years ago

4(2x+8)=5(x+4)solve for X​

4(2x+8)=5(x+4)solve for X