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kirza4 [7]
3 years ago
12

Find the slope of the line that passes through the points. (1,2) and (-2,2)

Mathematics
2 answers:
Damm [24]3 years ago
5 0

Answer:

0

Step-by-step explanation:

the slope formula is y2-y1/x2-x1, plug it in, 2-2/-2-1, 0/-3 or 0

kondaur [170]3 years ago
4 0

Answer:

The slope is 0.

Step-by-step explanation:

To find the slope, first you have to use the slope formula of \displaystyle \frac{y_2-y_1}{x_2-x_1}.

y2=2

y1=2

x2=(-2)

x1=1

\displaystyle \frac{2-2}{(-2)-1}=\frac{0}{-3}=0

Therefore, the slope is 0.

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The equation y = mx + b is the slope-intercept form of a linear equation. Solve y = mx+ b for m.
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7 0
3 years ago
Find the distance between the points (5, -3) and (0, 2).
ohaa [14]

Answer:

Distance between points  (5, -3) and (0, 2) is √50 or 7.07

Step-by-step explanation:

We need to find distance between two points (5,-3) and (0,2)

The distance formula used is:

d= \sqrt {\left( { x_2-x_1 } \right)^2 + \left( {y_2-y_1} \right)^2 }

here

x₁= 5, y₁=-3, x₂=0 and y₂=2

Putting values in the formula:

d= \sqrt {\left( {x_2-x_1} \right)^2 + \left( {y_2-y_1} \right)^2 }\\d= \sqrt {\left( {0-5} \right)^2 + \left( {2-(-3)} \right)^2 }\\d= \sqrt {\left( {-5} \right)^2 + \left( {2+3} \right)^2 }\\d= \sqrt {25+25}\\d= \sqrt {50}\\d= 7.07

So, distance between points  (5, -3) and (0, 2) is √50 or 7.07

7 0
3 years ago
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Vlada [557]
Ax + By = C. -A/B is the slope and C is intercept
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3 years ago
How would I figure this out?
andrew-mc [135]

Answer:

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3 0
3 years ago
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