Answer:
y2 = m(x2-x1)+y1
Step-by-step explanation:
Given the expression;
m = y2-y1/x2-x1
Making y2 the subject of the formula
Cross multiply
m(x2-x1) = y2-y1
Add y1 to both sides
m(x2-x1)+y1 = y2-y1+y1
m(x2-x1)+y1 = y2
Hence y2 = m(x2-x1)+y1
Answer: C) -4
Step-by-step explanation:
2 pages back to back.....x and x + 1
x + x + 1 = 203
2x + 1 = 203
2x = 203 - 1
2x = 202
x = 202/2
x = 101
x + 1 = 101 + 1 = 102
the 2 page numbers are : 101 and 102
Answer:
4(x-5)=92
4x-20=92
4x=92+20 (as we shifted - 20 to other side, it becomes +)
4x=112
x=112/4
x=28
Therefore the x=28
