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-Dominant- [34]

3 years ago

10

You can calculate the interest on a savings account by using this formula: interest = principal × rate × time if mary deposits $

275 in principal at an interest rate of 3.2 percent, how much interest will she earn in one year?

1 answer:

Valentin [98]3 years ago

7 0

I=prt
I=275×0.032×1
I=8.8

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in 3 months Us energy giant Enron went from a company with assets of 62bn to a company with depts of 18bn What is the difference

Kaylis [27]

Its just 62-18 so it would be 44bn

7 0

3 years ago

Determine whether the value is from a discrete or continuous data set. Number of coins in a jar is 78 number of coins in a jar i

Phoenix [80]

Determine whether the value is from a discrete or continuous data set. Number of coins in a jar is 78 number of coins in a jar is 78

Answer: Number of coins in a jar is from a discrete data set. Because the given variable is countable in a finite amount of time.

If a variable can take on any value between two specified values, it is called a continuous variable; otherwise, it is called a discrete variable.

3 0

3 years ago

Someone please be awesome and help me please :(

solong [7]

Answer:

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared. Whatever you add in, you must take out.

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

Now we are read to write that one part (the first three terms together) as a square:

$(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

I don't see this but what happens if we find a common denominator for those 2 terms after the square. (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

$(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0$

They put it in ( )

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

I'm going to go ahead and combine those fractions now:

$(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0$

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

$(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0$

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

$x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}$

$x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}$

Now subtract b/(2a) on both sides:

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Combine the fractions (they have the same denominator):

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

6 0

3 years ago

Suppose you invest $7500 at an annual interest rate of 4.2% compounded continuously. How much will you have in the account after

tatyana61 [14]

<span>Interest=principle x rate x time (in years)
so putting values so
Interest=7500 (.042)(2)
so
Interest=630 7500+630=8130
Interest=500 (.071)(4)
Interest=142 500+142=64
hope it helps</span>

6 0

3 years ago

Does anyone know how tj do this (trig)

Crank

Answer:

x = 5

Step-by-step explanation:

NOTE: THE 2 SIDES ARE THE SAME LENGTH

THEY HAVE TO BE SMALLER THEN 10

So 10/2 = 5

x = 5

<em><u>Please mark as brainliest </u></em>

Have a great day, be safe and healthy

Thank u

XD

8 0

3 years ago