Consider the steps for determining the quotient of ¹24 + x4
1 answer:
The simplified form of the expression has a numerator (x + 9)(2x + 1) and the denominator (x + 7) and the expression doesn't exist at (x = 9).
<h3>How to illustrate the quotient?</h3>The given expression is:
= [(3x² - 27x)/(2x² + 13x - 7)]/(3x/4x² - 1)
Firstly, factorize the expression 4x² - 1.
4x² - 1 = (2x - 1)(2x + 1)
Then, factorize 2x² + 13x - 7.
2x² + 13x - 7 = 2x² + 14x - x - 7
2x(x + 7) - 1(x + 7)
= (2x - 1)(x + 7)
Then, factorize the equation 3x² - 27x.
3x² - 27x = 3x(x - 9)
The factorized terms will be substituted into the equation. This will be:
= [3x(x - 9)/(2x - 1)(x + 7)] / 3x[(2x - 1)(2x + 1)]
= (x + 9)(2x + 1)/(x + 7)
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First convert the mixed number into an improper fraction. We do this by multiplying the denominator to the whole number, adding it to the numerator, which becomes our new numerator, and we keep the denominator the same:
When dividing fractions we flip(the reciprocal) the one we're dividing by and multiply:
Multiply the numerators and denominators together:
Simplify by dividing:
So it rained for 10 hours.