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3 years ago

HELP HELP PLEASE!!!! Will give what ever u want

Mathematics

1 answer:

SCORPION-xisa [38]3 years ago

6 0

5c+5d+8c+4d or the simplified version is 13c+9d

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How many 3/4 foot pieces of string can be cut from a piece of string 4 1/2 feet long

Gnom [1K]

3/4 foot is 9 inches, and 4 1/2 feet is 54 inches, so, 54/9 makes exactly 6 pieces of string.

8 0

3 years ago

Graham sold six magazines less than double what Adriannne sold, a. Which of the following expressions represents Graham’s sales

Eva8 [605]

The best and most correct answer among the choices provided by your question is the fourth option or letter D. The expression that represents Graham's sales is 2a − 6. Twice the sales of Adrianne, deducted by 6 should be Graham's sales.

Hope this helps!

6 0

3 years ago

ANSWER THIS PLEASE ASAP

Talja [164]

Answer: a.) 72 of each type of animal, for a total of 216

b.) 16 grown cats, 4 kittens

Step-by-step explanation:

part a. It's a distribution (division) problem. The same number of each animal is distributed over some unknown number of troughs, but the total number of troughs adds up to 69. ( I hate to give this all away, as its a brilliant problem! )

Number of troughs for each animal type is How many needed by the number of animals per trough:

h/2 + c/3 + p/8 = 69

Since we are given "the same number of horses, cows and pigs" we can substitute "x" for all.

$\frac{x}{2} + \frac{x}{3} +\frac{x}{8} = 69$ Get a common denominator. 24 would work, 48 also.

$48(\frac{x}{2} +\frac{x}{3} +\frac{x}{8} ) = 48(69)$

24x + 16x + 6x = 3372

46x = 3372 x = 72

Proof: calculate the number of each kind of trough

Horses 72/2 = 36, Cows 72/3 = 24 Pigs 72/8 = 9 36+24+9 = 69

part b. 5c + 3k = 92, c + k = 20 Rearrange to get a value for c to substitute.

c = 20-k 5(20-k) +3k =92 Distribute and solve

100 - 5k + 3k = 92 becomes -2k = -8 so k = 4 Substitute into the original

c + 4 = 20 becomes c=20-4, so c = 16

Proof: 5c +3k = 92 Substitute values 5(16) + 3(4) = 92 80 + 12 = 92

6 0

3 years ago

10 points, please help me and explain how to do this with answers!

8_murik_8 [283]

$\bf f(x)=log\left( \cfrac{x}{8} \right)\\\\
-----------------------------\\\\
\textit{x-intercept, setting f(x)=0}
\\\\
0=log\left( \cfrac{x}{8} \right)\implies 0=log(x)-log(8)\implies log(8)=log(x)
\\\\
8=x\\\\
-----------------------------$

$\bf \textit{y-intercept, is setting x=0}\\
\textit{wait just a second!, a logarithm never gives 0}
\\\\
log_{{ a}}{{ b}}=y \iff {{ a}}^y={{ b}}\qquad\qquad 
% exponential notation 2nd form
{{ a}}^y={{ b}}\iff log_{{ a}}{{ b}}=y 
\\\\
\textit{now, what exponent for "a" can give you a zero? none}\\
\textit{so, there's no y-intercept, because "x" is never 0 in }\frac{x}{8}\\
\textit{that will make the fraction to 0, and a}\\
\textit{logarithm will never give that, 0 or a negative}\\\\
$

$\bf -----------------------------\\\\
domain
\\\\
\textit{since whatever value "x" is, cannot make the fraction}\\
\textit{negative or become 0, , then the domain is }x\ \textgreater \ 0\\\\
-----------------------------\\\\
range
\\\\
\textit{those values for "x", will spit out, pretty much}\\
\textit{any "y", including negative exponents, thus}\\
\textit{range is }(-\infty,+\infty)$
p, li { white-space: pre-wrap; }

----------------------------------------------------------------------------------------------

now on 2)

$\bf f(x)=\cfrac{3}{x^4}$ if the denominator has a higher degree than the numerator, the horizontal asymptote is y = 0, or the x-axis,

in this case, the numerator has a degree of 0, the denominator has 4, thus y = 0

vertical asymptotes occur when the denominator is 0, that is, when the fraction becomes undefined, and for this one, that occurs at $x^4=0\implies x=0$ or the y-axis

----------------------------------------------------------------------------------------------

now on 3)

$\bf f(x)=\cfrac{1}{x}$

now, let's see some transformations templates

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\

\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\mathbb{R}^{{{ B}}x+{{ C}}}+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\
\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\
\qquad if\ {{ D}}\textit{ is positive, upwards}
\end{array}$

now, let's take a peek at g(x)

$\bf \begin{array}{lcllll}
g(x)=&-&\cfrac{1}{x}&+3\\
&\uparrow &&\uparrow \\
&\textit{upside down}&&
\begin{array}{llll}
\textit{vertical shift up}\\
\textit{by 3 units}
\end{array}
\end{array}$

3 0

3 years ago

Y=5*2^x describe the graph of the function

vladimir2022 [97]

The graph is quadratic

3 0

3 years ago

Read 2 more answers