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3 years ago

5x - y = -3 in slope intercept form?

Mathematics

2 answers:

mixas84 [53]3 years ago

6 0

5x-y=-8 | subtract 5x from both sides.

-y = -5x - 8 | divide both sides by -1

y = 5x + 8 Done.

BartSMP [9]3 years ago

3 0

Move 5x to opposite side so -y = -5x - 3 change all negatives to positive so ur answer is y = 5x + 3

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The total number of faculty members is 442. The school reported that it had 6 professors to every 11 lecturers. How many of each

Musya8 [376]

The school has 156 professors and 286 lectures

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2 years ago

Which of the following points is in the solution set of y < x2 - 2x - 8?<br>(-2, -1)(0, -2)(4, 0)

ratelena [41]

Y < (x - 4)(x + 2)

so the critical points are -2 and 4
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the answer is ((-2,-1)

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3 years ago

Read 2 more answers

Please help!

Tcecarenko [31]

1. -1/3 - (-1/2) = .16666666666666

2. -8

Hope it helps, if you need it in fractions, you can always convert it :)

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3 years ago

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One estimate shows that the number of people without access to safe drinking water is about one billion. How much water is requi

gizmo_the_mogwai [7]

Answer:

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3 0

2 years ago

The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i

kicyunya [14]

Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.

Recall the formula for the sum of consecutive positive integers,

$\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2$

Now,

$1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016$

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

$\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224$

numbers, and their sum is

$\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400$

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of $1+9\times2=19$ .

So, the sum of the first 1234 terms in the sequence is 2419.

8 0

1 year ago