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expeople1 [14]
3 years ago
9

A scientist conducted an experiment. Due to chemical reaction, the temperature of a compound rose 1/10 degree every 1/4 hour for

a limited time. What was the rate , in degrees per hour that the temperature of the compound rose.
Mathematics
1 answer:
klio [65]3 years ago
5 0

Answer:

The rate is \frac{2}{5} degree per hour.

Step-by-step explanation:

Given : A scientist conducted an experiment. Due to chemical reaction, the temperature of a compound rose \frac{1}{10} degree every \frac{1}{4} hour for a limited time.

To find : What was the rate, in degrees per hour that the temperature of the compound rose ?

Solution :

In every \frac{1}{4} hour the temperature of a compound rose \frac{1}{10} degree

To get  the rate, in degrees per hour,

In every 1 hour the temperature of a compound rose is

r=\dfrac{\frac{1}{10}}{\frac{1}{4}} degree

r=\dfrac{4}{10} degree/hr

r=\dfrac{2}{5} degree/hr

Therefore, the rate is \frac{2}{5} degree per hour.

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Answer:

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Therefore, the only reasonable quotient in the given options is 609.

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