The perimeter of a square is the sum of its sides and they
are all equal, so to obtain the length of each of them we divide the perimeter
of the first fence between 4:
P1= 64 feet/4 sides
P1= 16 feet
Then, the length of each side of the second fence will
increase 2 feet at each end, as shown in the figure. We have then that the
perimeter of the second fence is:
P2 = 20 feet x 4 sides
P2 = 80 feet
The sum of the perimeters of both fences is:
PT = P1 + P2
PT = 64 feet + 80 feet
PT = 144 feet
Total cost = 1.17 $ x 144 feet
Total cost = 168.48 $
The total cost of the fences was $ 168.48
Answer:
was there more
Step-by-step explanation:
(i will edit answer)
Given:
The two points are (0, -2) and (9, 10).
To find:
The distance between the given points.
Solution:
Distance between the two points is
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
Using the above distance formula, the distance between given points is
![d=\sqrt{(9-0)^2+(10-(-2))^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%289-0%29%5E2%2B%2810-%28-2%29%29%5E2%7D)
![d=\sqrt{(9)^2+(10+2)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%289%29%5E2%2B%2810%2B2%29%5E2%7D)
![d=\sqrt{81+(12)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B81%2B%2812%29%5E2%7D)
On further simplification, we get
![d=\sqrt{81+144}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B81%2B144%7D)
![d=\sqrt{225}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B225%7D)
![d=15](https://tex.z-dn.net/?f=d%3D15)
Therefore, the distance between the given points (0,-2) and (9,10) is 15 units.