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OverLord2011 [107]
3 years ago
6

Whet is 1000% of 100%

Mathematics
1 answer:
Brut [27]3 years ago
3 0
The answer would be 1,000
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Which relationship in the triangle must be true ?
Ivan

Answer:

Choice B. sin(B)=cos(90-B)

Step-by-step explanation:

That cofunction identity is the one you looking for...choice B.

If you aren't convinced or don't know that identity, then maybe this will help:

90-B is actually the same thing as saying A for this right triangle since A+B=90.

So choice B basically says sin(B)=cos(A)

Well let's find both sin(B) and cos(A)

sin(B)=b/c

cos(A)=b/c

Those are the same ratios!

So they are equal!

3 0
2 years ago
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If anyone can solve this quickly I will give brainly
Nataly [62]

Answer:

m∠BFE  = 171º

BE = 219º

Step-by-step explanation:

∠BFE is supplementary to ∠EFC

m∠BFE  = 180 - 9

m∠BFE  = 171º

--------------------------

The angle between two chords is equal to half the sum of the intercepted arcs:

∠BFE = (DC + BE)2

171 = (123 + BE)/2

342 = 123 + BE

219º = BE

6 0
3 years ago
(2p + 4) + 5 (p-1) - (p+7)
jonny [76]

<em>Your answer will be, </em><em>"6p - 8"</em>

Thanks,

<em>Deku ❤</em>

6 0
3 years ago
A sequence is defined recursively using the formula f(n + 1) = –0.5 f(n) . If the first term of the sequence is 120, what is f(5
Svetllana [295]
7.5
f(1) = 120
f(2) = -60
f(3) = 30
f(4) = -15
f(5) = 7.5
6 0
3 years ago
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Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children
Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem, we have that:

p = 0.69

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}

0.07\sqrt{n} = 1.2996

\sqrt{n} = \frac{1.2996}{0.07}

\sqrt{n} = 18.5658

(\sqrt{n})^{2} = (18.5658)^{2}

n = 345

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

4 0
3 years ago
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