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Ber [7]
3 years ago
11

Which value is a solution of the equation 2 – 8x = –6?

Mathematics
1 answer:
natulia [17]3 years ago
5 0
Simple....

Which value is a solution of the equation 2 – 8x = –6?(1 point)• 1• –1• 8
You have: 2-8x=-6

plug n chug...

2-8(1)=-6

2-8=-6

-6=-6 (Yes)  (<<---Answer)

2-8(-1)=-6

2+8=-6

10=-6 (No)

2-8(8)=-6

2-64=-6

-62=-6 (No)

3. Which ordered pair is a solution of the equation y = x – 4?(1 point)• (2, 6)• (6, 2)• (–2, 6)• (–6, 2)
Plug n chug.....

you have:y=x-4

(2,6)

6=2-4

6=-2 (No)

(6,2)

2=6-4

2=2 (Yes) (<<<---Answer)

(-2,6)

6=-2-4

6=-6 (No)

(-6,2)

2=-6-4

2=-10 (No)

4. Which ordered pair is a solution of the equation y = 4x?(1 point)• (1, 3)• (–1, –4)• (–4, –1)• (1, –4)
You have: y=4x

(1,3)

3=4(1)

3=4 (No)

(-1,-4)

-4=4(-1)

-4=-4 (Yes) (<<<----Answer)

(-4,-1)

-1=4(-4)

-1=-16 (No)

(1,-4)

-4=4(1)

-4=4 (No)

5. Which ordered pair is a solution of the equation y = –9x + 4?(1 point)• (10, –86)• (–4, –58)• (6, –41)• (–6, 57)

You have: y=-9x+4

(10,-86)

-86=-9(10)+4

-86=-90+4

-86=-86 (Yes) (<<<---Answer)

(-4,-58)

-58=-9(-4)+4

-58=36+4

-58=40 (No)

(6,-41)

-41=-9(6)+4

-41=-54+4

-41=-50 (No)

(-6,57)

57=-9(-6)+4

57=54+4

57=58 (No)

6. Mike and his best friend Dan have the same birthday, but Mike is three years older than Dan. Let the variable x represent Mike’s age and y represent Dan’s age. Which graph represents the relationship between Dan’s age and Mike’s age?(1 point)

There is no graph.

7. Solve the following equation.
–4 = g + 1(1 point)• g = –4• g = 4• g = –5• g = –3
You have: -4=g+1

-4=g+1
-1     -1

-5=g (Answer/C)

8. Solve the following equation. 
x – 3 = –5(1 point)• x = • x = –2• x = –8• x = 15
You have: x-3=-5

x-3=-5
  +3  +3

x=-2 (Answer)
9. Solve the following equation.
2.8 = 2y(1 point)• y = 1.4• y = • y = 2.8• y = 0.6

You have: 2.8=2y

2.8=2y

\frac{2.8}{2} = \frac{2y}{2}

1.4=y (Answer)

10. 
Solve the following equation. 

–8 = 
(1 point)
• z = –
• z = –5
• z = –24
• z = 
11. 
Solve the following equation.

–9 = 
(1 point)
• n = 
• n = 
• n = 
• n = 

NUMBER 10 AND 11..THERE IS NOTHING I CAN WORK WITH,THEREFORE I CAN NOT GIVE AN ANSWER....

12. 
Which equation is an identity?
(1 point)
• 11 – (2v + 3) = –2v – 8
• 5w + 8 – w = 6w – 2(w – 4)
• 7m – 2 = 8m + 4 – m
• 8y + 9 = 8y – 3

You have:

11-(2v+3)=-2v-8

11-2v-3=-2v-8

-2v+8=-2v-8 (No)

5w+8-w=6w-2(w-4)

4w+8=6w-2w+8

4w+8=4w+8 (Yes) (<<<<--Answer)

7m-2=8m+4-m

7m-2=7m+4 (No)

8y+9=8y-3 (No)

13. 
Which equation has no solution?
(1 point)
• 8 – (5v + 3) = 5v – 5
• 3m – 6 = 5m + 7 – m
• 3w + 4 – w = 5w – 2(w – 2)
• 7y + 9 = 7y – 6

You have:

8-(5v+3)=5v-5

8-5v-3=5v-5

-5v+5=5v-5
      +5         +5
-5v+10=5v
+5v      +5v

10=10v

1=v

3m-6=5m+7-m

3m-6=4m+7
-3m    -3m

-6=m+7
-7      -7 

-13=m

3w+4-w=5w-2(w-2)

2w+4=5w-2w+4

2w+4=3w+4
-2w    -2w

4=w+4
-4    -4

0=w

7y+9=7y-6
-7y     -7y

NO SOLUTION  (ANSWER)

Thus, your answer.
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torisob [31]

The function is y = 1/2 x² - 2 x and the base of the triangle cannot be 3 cm.

let the base of the triangle be x

Height of the triangle = x - 4

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Area = 1/2 (x² - 4x)

Area = 1/2 x² - 2 x

We can also write it as a function:

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Domain = (3 , ∞)

Range = [0, ∞)

Since 3 is not included in the domain, base of the triangle cannot be 3 cm.

Therefore, the function is y = 1/2 x² - 2 x and the base of the triangle cannot be 3 cm.

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ICE Princess25 [194]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Dont know where to start any help please<br><br><br> solve for u<br><br> 8=u/12.8
kherson [118]
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4 years ago
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Let a "binary code" be the set of all binary words, each consisting of 7 bits (i.e., 0 or 1 digits). For example, 0110110 is a c
Dmitry_Shevchenko [17]

Answer:

a) 128 codewords

b) 35 codewords

c) 29 codewords

Step-by-step explanation:

a) Each 7 bits consist of 0 or 1 digits. Therefore the first bit is two choices (0 or 1), the second bit is also two choices (0 or 1), continues this way till the last bit.

So total number of different code words in 7 bits is 2×2×2×2×2×2×2 = 2⁷ = 128

There are 128 different codewords.

b) A code word contains exactly four 1's this means that  it has four 1's and three 0's . Therefore, in 7 bits, we have four of the same kind and three of the same kind. Hence, total number of code words containing exactly four 1's =7!/(4!*3!) = 35 codewords

c) number of code words containing at most two 1's  = codewords containing zero 1's + words containing one 1's + words containing two 1's

Now codewords containing zero 1's = 0000000 so 1 word

Codewords containing one 1's = 1000000,0100000,0010000,0001000,0000100,0000010,0000001. That's seven words

Codewords containing two 1's means word containing two 1's and five 0's. So out of seven, two are of one kind and five are of another kind

Therefore, the total number of such words=7!/(2!*5!)=21

Hence, codewords having at most two 1's = 21+7+1 =29 codewords

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3 years ago
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The line from the point to its reflection should be perpendicular.If we imagine a line from (5,7) to (2,2), it would have a slope of (2-7)/(2-5) = 5/3.

For that line to be perpendicular to y=-2/5x+6, their slopes should be each other's negative reciprocals.

-2/5 negative reciprocal is 5/2, which is not equal to our calculated 5/3, so (2,2) cannot be the reflected point. Evan was wrong.

Q1-74: AB have slope 6/5, C has -5/6, D 6/5, E -5/6 again.
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