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PSYCHO15rus [73]
3 years ago
10

What kind of solution(s) does ax^2-bx+c=0 have if b^2-4ac<0?

Mathematics
2 answers:
yawa3891 [41]3 years ago
8 0
The discriminant is the value that is b^2 - 4ac.
When this number is <0 there will be 2 complex solutions. Letter D.

You would be taking the sqrt of a negative number resulting in a
" +- i sqrt of a number"
vova2212 [387]3 years ago
8 0
Liike the other user said

when the discriminant is less than 0, you get 2 complex roots

D is the answer
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Money left to save: $14

Time left to save: 4 weeks

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Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

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15 time the difference of 14 and 6
Sloan [31]

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5 0
3 years ago
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Solve 3/3x + 1/x+4 = 10/7x solve for x
wariber [46]

Answer:

x = 14/3 + sqrt(217)/3 or x = 14/3 - sqrt(217)/3

Step-by-step explanation:

Solve for x:

x + 4 + 1/x = (10 x)/7

Bring x + 4 + 1/x together using the common denominator x:

(x^2 + 4 x + 1)/x = (10 x)/7

Cross multiply:

7 (x^2 + 4 x + 1) = 10 x^2

Expand out terms of the left hand side:

7 x^2 + 28 x + 7 = 10 x^2

Subtract 10 x^2 from both sides:

-3 x^2 + 28 x + 7 = 0

Divide both sides by -3:

x^2 - (28 x)/3 - 7/3 = 0

Add 7/3 to both sides:

x^2 - (28 x)/3 = 7/3

Add 196/9 to both sides:

x^2 - (28 x)/3 + 196/9 = 217/9

Write the left hand side as a square:

(x - 14/3)^2 = 217/9

Take the square root of both sides:

x - 14/3 = sqrt(217)/3 or x - 14/3 = -sqrt(217)/3

Add 14/3 to both sides:

x = 14/3 + sqrt(217)/3 or x - 14/3 = -sqrt(217)/3

Add 14/3 to both sides:

Answer:  x = 14/3 + sqrt(217)/3 or x = 14/3 - sqrt(217)/3

8 0
3 years ago
8(x+1)-7x ≥-3 help me find the solution
Ann [662]

Answer:

x \geq 11

Step-by-step explanation:

8\left(x+1\right)-7x

8x+8-7x

x+8

Then..

x+8\ge \:-3

Subtract 8 from both sides

x+8-8\ge \:-3-8

Then, you got your awnser.

x\ge \:-11

7 0
3 years ago
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