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Brut [27]
3 years ago
7

Plzzzzzzzz help I dont get it xoxo

Mathematics
1 answer:
olasank [31]3 years ago
4 0

Answer:

the answer can be 1 I guess

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Find the missing part. L=8, w=4, h=2. Find the diagonal of (d) of the retangular solid
marusya05 [52]

The diagonal of the rectangular solid is d=2 \sqrt{21}

Explanation:

The length of the rectangular solid is l=8

The width of the rectangular solid is w=4

The height of the rectangular solid is h=2

We need to determine the diagonal of the rectangular solid.

The diagonal of the rectangular solid can be determined using the formula,

d=\sqrt{l^{2}+w^{2}+h^{2}}

Substituting the values l=8, w=4 and h=2 , we get,

d=\sqrt{8^{2}+4^{2}+2^{2}}

Squaring the terms, we get,

d=\sqrt{64+16+4}

Adding the terms, we have,

d=\sqrt{84}

Simplifying, we have,

d=2 \sqrt{21}

Thus, the diagonal of the rectangular solid is d=2 \sqrt{21}

8 0
4 years ago
Harvey can read 17 pages in one hour. In one week, he spent 6 hours reading. How many pages did Harvey read that week?
USPshnik [31]

Answer:

102

Step-by-step explanation:

If he read 17 pages in one hour and spent 6 hours reading then you have to do 17 times 6 which is 102.

3 0
3 years ago
Kite A B C D is shown. Lines are drawn from point A to point C and from point B to point D and intersect. In the kite, AC = 10 a
Oduvanchick [21]

Answer:

30 u^{2}

Step-by-step explanation:

The computation of the area of kite ABCD is shown below:

Given data

AC = 10 ;

BD = 6

As we can see from the attached figure that the Kite is a quadrilateral as it involves two adjacent sides i.e to be equal

Now the area of quadrilateral when the diagonals are given

So, it is

\text { area of kite }=\frac{1}{2} \times d_{1} d_{2}

where,

d_{1}=10\ and\ d_{2}=6

So, the area of the quadrilateral is

=\frac{1}{2}(10)(6)\\\\=30 u^{2}

4 0
3 years ago
Using a graphing calculator (desmos.com) graph and screenshot the following graphs:
Setler [38]
The graphs are attached.  Each graph is transformed by a horizontal translation or vertical translation or a reflection.

4 0
3 years ago
What are the coordinates of the endpoints of the midsegment for △DEF that is parallel to DE¯¯¯¯¯?
Vladimir [108]

Answer:

(-1, 2) and (-1, 3.5)

Step-by-step explanation:

The triangle ΔDEF spans 4 squares horizontally.

So, the midsegment of ΔDEF will coincide with the line 4/2 = 2 squares from the vertex F.

Note that the <em>x </em>coordinate of the vertex F is -3 and 2 units to the right of F is -1.

Therefore, the midsegment of ΔDEF coincides with the line <em>x</em> = -1.

So, the <em>x</em> coordinates of the end points of the midsegment are -1.

Let's find the <em>y</em> coordinates of the end points.

From the given figure, it is clear that the mid point of FD is half way between 3 and 4 and hence it is 3.5.

Mid point of FE is 2.

So, the co-ordinates of the end points of the midsegment are (-1, 2) and (-1, 3.5).



8 0
3 years ago
Read 2 more answers
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