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Sunny_sXe [5.5K]
3 years ago
15

Non example of a ratio tables

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
5 0

Answer:

0,4, 2,10 4,16, 6,22

Step-by-step explanation:

I really hope dis helps good luck

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Suppose you have a coin collection of dimes and quarters containing 46 coins. If you have 6.70 dollars, how many of each type of
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Answer:

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Step-by-step explanation:

Here, the total number of coins combined = 46

Let us assume the number of dimes = m

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Now,as we know:

1 dime = $0.1

So, m dimes  = m x ($0.1) = $(0.1 m)

1 Quarter  = $0.25

So, ( 46 - m ) Quarters  = (46 - m ) x ( $ 0.25)   = 11.5 - 0.25 m

Also, given the total amount of coins = $ 6.70

⇒ Value of (Dimes + Quarters) = $ 6.70

or, (0.1 m) +  11.5 - 0.25 m  = 6.70

-0.15 m = - 4.8

or, m = 4.8/0.15  =  32

⇒ m = 32

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