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kherson [118]
3 years ago
9

Exodus Limousine Company has $1,000 par value bonds outstanding at 15 percent interest. The bonds will mature in 30 years. Compu

te the current price of the bonds if the percent yield to maturity is:
a. 4 percent

b. 8 percent

Calculate the final answer up to two decimal places. Use Appendix B and Appendix D for an approximate answer but calculate your final answer using the formula and financial calculator methods. Assume interest is paid annually.
Business
1 answer:
nasty-shy [4]3 years ago
7 0

Answer:

if YTM at 4% price :  $2,902.1237

if YTM at 8% price :  $1,788.0448

The bonds are above face value asthey offer a higher coupon payment than the market yield therefore the bond holders are willing to pay above theri face value

Explanation:

the market price of the bond will be the present value of coupo payment and maturity:

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\

C 150.000

time 30

rate 0.04

150 \times \frac{1-(1+0.04)^{-30} }{0.04} = PV\\

PV $2,593.8050

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity   1,000.00

time   30.00

rate  0.04

\frac{1000}{(1 + 0.04)^{30} } = PV  

PV   308.32

PV c $2,593.8050

PV m  $308.3187

Total $2,902.1237

No we repeat the process with the yield at 8%

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\

C 150.000

time 30

rate 0.08

150 \times \frac{1-(1+0.08)^{-30} }{0.08} = PV\\

PV $1,688.6675

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity   1,000.00

time   30.00

rate  0.08

\frac{1000}{(1 + 0.08)^{30} } = PV  

PV   99.38

PV c $1,688.6675

PV m  $99.3773

Total $1,788.0448

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Answer: ∑Tₓ = 201.222

time required to complete the last two units is 201.222 minutes

Explanation:

Given that,

total time required to four units is 600 hours,

Learning curve applied is 75% and from the learning curve coefficient table, total time factor to complete four units at 75% learning curve is 2.946

so

∑Tₙ = T₁ × total time factor

{ ∑Tₙ is total time required to complete all the units which is 600 hrs, T₁ is Time for first unit, total time factor = 2.946 }

we substitute

∑T₄ = ∑T₁ × total time factor

600 = ∑T₁ × 2.946

∑T₁  = 600/2.946

∑T₁  = 203.666 minutes

Now to get the total time required to complete 6 units, we say:

∑T₆ = ∑T₁ × total time factor

Note that total time factor at this point changes;

( from the learning curve coefficient table, total time factor to complete 6 units at 75% learning curve is 3.934)

so we substitute

∑T₆ = 203.666 × 3.934

∑T₆ = 801.222

Now to find how long should it take them to finish the last two units, we say

∑Tₓ = ∑T₆ - ∑T₄

∑Tₓ = 801.222 - 600

∑Tₓ = 201.222

Therefore time required to complete the last two units is 201.222 minutes

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