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Evgesh-ka [11]
4 years ago
15

Imara used these steps to find the length of the hypotenuse of the right triangle. Step 1: Find the area of the square with side

lengths of 20: 400 Step 2: Find the area of the square with side lengths of 15: 225 Step 3: Find the sum of the areas of the two squares: 625 Step 4: State the length of the hypotenuse: 625 Which best describes Imara’s error? She should have found the area of the square with side lengths of 15 first. She did not correctly calculate the area of the square with side lengths of 15. She should have found the sum of 15 and 20 and then squared the sum. She did not find the side lengths of the square with an area of 625.
Mathematics
2 answers:
Strike441 [17]4 years ago
3 0

Answer:

Imara's error will be that she did not find the side lengths of the square with an area of 625.

Step-by-step explanation:

Imara used these steps to find the length of the hypotenuse of the right triangle.

Step 1: Find the area of the square with side lengths of 20 i.e. 400

Step 2: Find the area of the square with side lengths of 15 i.e. 225

Step 3: Find the sum of the areas of the two squares i.e. 625

Step 4: State the length of the hypotenuse i.e. 625

Therefore, Imara's error will be that she did not find the side lengths of the square with an area of 625. (Answer)

Alchen [17]4 years ago
3 0

Answer:

D

Step-by-step explanation:

XD

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Answer:

The answer is C

Step-by-step explanation:

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8 0
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<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if the proportion is of 0.5, that is:

H_0: p = 0.5


At the alternative hypothesis, it is tested if the proportion is different of 0.5, that is:

H_1: p \neq 0.5.

<h3>What is the test statistic?</h3>

The test statistic is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

In which:

  • \overline{p} is the sample proportion.
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  • n is the sample size.

In this problem, the parameters are:

p = 0.5, n = 12, \overline{p} = \frac{10}{12} = 0.8333

Then, the value of the test statistic is as follows:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

z = \frac{0.8333 - 0.5}{\sqrt{\frac{0.5(0.5)}{12}}}

z = 2.31

<h3>What is the decision?</h3>

Considering a <em>two-tailed test</em>, as we are testing if the proportion is different of a value, with a <em>significance level of 0.05</em>, the critical value is of |z^{\ast} = 1.96.

Since the absolute value of the test statistic is greater than the critical value for the two-tailed test, it is found that there is enough evidence to conclude that the proportion of participants that had improved androstenone-detection accuracy is different of 50%.

More can be learned about the z-distribution at brainly.com/question/26454209

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