<span>6x2 -5x –3 = 0
a = 6 b=-5 and c=-3
x = [-b +-sq root (b² -4ac)] / 2a
x = [--5 +-sq root (25 -4*6*-3)] / 2*6
x = [5 +- sq root (25 +72)] / 12
x = [5 +- sq root (97)] / 12
x1 = [5 + </span><span><span><span>9.8488578018
</span>
</span>
</span>
] / 12
x1 =
<span>
<span>
<span>
14.8488578018
</span>
</span>
</span>
/ 12
x1 =
<span>
<span>
<span>
1.2374048168
</span>
</span>
</span>
x2 = [5 -
<span>
<span>
<span>
9.8488578018
</span>
</span>
</span>
] / 12
x2 =
<span>
<span>
<span>
-4.8488578018
</span>
</span>
</span>
/ 12
x2 =
<span>
<span>
<span>
-0.4040714835
</span>
</span>
</span>
Answer:
pls tell me where cory bought them from. its a very cheap price . i want to buy
Step-by-step explanation:
Answer:
Step-by-step explanation:
domain (ur x values) = -3,-1,1,2
range (ur y values) = -3,1,2,4
do not have to write them more then once
answer is C
The total labor year cost increase is 15,000
Answer:
Airplane #1 equation: y=5/13x+42/13
Airplane #2 equation: y=1/3x+14
Step-by-step explanation:
So to find the slope of each airplane, you use the formula y2-y1/x2-x1. That means, for airplane#1 the equation will be 9-4/15-2. Simplify this and get 5/13. Then, for airplane#2, the equation will be 12-9/6-15. Simplify this and get 3/-9 and divide each side by 3 to get 1/-3 or -1/3. Next, use point slope formula to find the system of linear equations. Point slope formula is y-y1=m(x-x1). M is the slope. Use any point from the line. In this case, I will use (2,4). Tat means the first airplane's equation would be y-4=5/13(x-2). Then y-4=5/13x-10/13. Then, convert four into a fraction with a denominator of 13. This means, you have to multiply 4 by 13 to get 52/13. Add 52/13 to -10/13 to get 42/13. That means the first equation will be y=5/13x+42/13. The second equation point will be (6,12). This means the equation will be y-12=-1/3(x-6). Simplify this to get y-12=-1/3x+2. Simplify this to get y=1/3x+14. Therefore, Airplane#1 equation will be y=5/13x+42/13 and airplane #2 equation will be y=1/3x+14.
Hope this helps
