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3 years ago

If GH = 3 and HJ = 5, then G ___ J.

Mathematics

2 answers:

ELEN [110]3 years ago

7 0

Here is your answer

$>$

REASON:

We know that the angle opposite to greater side of a triangle is greater.

i.e. The side which is greater in length will have greater angle on its opposite vertex.

Since,

HJ= 5 and GH= 3

So, HJ > GH

using above relation...

G>J (opposite angles of the side)

HOPE IT IS USEFUL

Leokris [45]3 years ago

3 0

i tried my best without doing work srry if its wrong

Have a good day bro!!!

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Graph x > 2

Andrews [41]

Answer:

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Step-by-step explanation:

Because when you draw the graph you see that x is larger than 2 , and 2 is not including in the solution so, we just make a small lines (forget the y-axis).

I hope that it's a clear solution and explanation.

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3 years ago

Suppose that the exchange rate from U.S. dollars to Canadian dollar is 1 U.S. dollar per 1.0028 Canadian dollars. Joey exchanges

Svetradugi [14.3K]

Answer:

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Step-by-step explanation:

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3 years ago

Calculate the frequency in hertz of photons of light with energy of 8.10 × 10-19 J.

stira [4]

The Planck–Einstein relation $E=hv$ gives that E, the photon energy, is equal to h, Planck's constant, times <span>ν</span>, the frequency.

We can solve the equation in terms of frequency to get
$v= \dfrac{E}{h}$

We substitute our given energy, $8.10 \times 10^{-19} J$ , and Planck's constant, $6.626 \times 10^{-34} Js$ .

$v= \dfrac{8.10 \times 10^{-19} J}{6.626 \times 10^{-34} Js}=1.22 \times 10^{15} s^{-1}=1.22 \times 10^{15} Hz$

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3 years ago

If the combined area of the white and orange regions is 100π, what is the area of ONLY the orange region? A) 16π B) 36π C) 64π D

kkurt [141]

The image is here, i am struggled with this problems too please help!

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3 years ago

Read 2 more answers

Determine the shortest segment in △ PQS and △ QRS. Remember that a segment is named by its endpoints (two letters).

irinina [24]

Answer: QS and QR are the shortest segment of the triangle ΔPQS, and ΔSQR respectively.

Step-by-step explanation:

Since we have given that

ΔPQS, and ΔSQR,

Consider, ΔPQS,

As we know that " the length opposite to the largest angle is the shortest segment."

So, According to the above statement.

$\angle QPS=63\textdegree\\\\\text{So, QS is the shortest segment of this triangle}$

Similarly,

Consider, ΔSQR,

Again applying the above statement, we get that,

$\angle QSR=75\textdegree\\\\\text{ So, QR is the shortest segment of this triangle}$

Hence, QS and QR are the shortest segment of the triangle ΔPQS, and ΔSQR respectively.

8 0

2 years ago