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jarptica [38.1K]
4 years ago
6

Number 10 I need help

Mathematics
1 answer:
nekit [7.7K]4 years ago
4 0

what is the question? you just gave us the information, there's no question here.

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Find the area of the shaded region - please just show your first step in this process.
erastovalidia [21]

Answer:

4x^3 - 3x^2 - 14x + 6 (this is the formula since we don't know x)

Step-by-step explanation:

[(4x-2) x (x^2 - 3)] - [(x+2) x (x)] = 4x^3 - 3x^2 - 14x + 6

4 0
3 years ago
A point x is 34m due to east of a point Y . The bearing of a flagpole from x and Y are N18°W And N40°E respectively .
Murljashka [212]

Answer:

The distance of flag post from Y is 38.13 m

Step-by-step explanation:

Consider point Y at the intersection of both lines as shown below. Now the point X lies 34 meter from point Y in east direction.  

Now flag pole at point X lies at a bearing of N18°W. That is at point X from north, flag post makes an angle of 18° towards west.  

Similarly flag pole at point Y lies at a bearing of N40°E. That is at point Y from north, flag post makes an angle of 40° towards east.  

Consider ∆ AXY as right angle triangle. Therefore measure of angle FXY is,  

\angle AXY=\angle AXF+\angle FXY

\therefore 90 \degree=18\degree+\angle FXY

\angle FXY=72\degree

Consider ∆ BYX as right angle triangle. Therefore measure of angle FYX is,  

\angle BYX=\angle BYF+\angle FYX

\therefore 90 \degree=40\degree+\angle FYX

\angle FYX=50\degree

Refer attachment 1.  

From diagram consider the triangle FYX. To find the third angle that is ∠YFX can be calculated by using angle sum property of triangle.

∠YFX+∠FYX+∠FXY=180°

∠YFX+50°+72°=180°

∠YFX=58°

Refer attachment 2.  

Now the distance FY can be calculated using sin rule as follows,  

\frac{\sin X}{FY}=\frac{\sin F}{YX}=\frac{\sin Y}{FX}

Substituting the values,

\frac{\sin 72}{FY}=\frac{\sin 58}{34}=\frac{\sin 50}{FX}

Simplifying first two terms,

\frac{\sin 72}{FY}=\frac{\sin 58}{34}

Cross multiplying,

34\times\sin 72=FY\times \sin 58

\dfrac{34\times\sin 72}{\sin 58}=FY

FY=38.13 m

7 0
3 years ago
HELPPPOOPOPPPP!!!! PLEASE
guajiro [1.7K]

The answer is....................................................

5 0
3 years ago
A rock is thrown upward at a speed of 69 mph when the rock reaches its peak how fast is it going and what is the magnitude and a
aleksandrvk [35]
At it's peak the rock is going 0mph the acceleration is .0000038 m/s^2 if on earth
6 0
3 years ago
Find an equation equivalent to (x-2)^2 + (y + 2)^2 = 8 in polar coordinates
Brilliant_brown [7]

The circle equation in polar coordinates is:

   r - 4*cos(\theta) + 4*sin(\theta) = 0

<h3>How to change the coordinates of the circle equation?</h3>

Here we have the circle equation:

(x - 2)^2 + (y + 2)^2 = 8

First, we expand it to:

x^2 - 4x + 4 + y^2 + 4y + 4 = 8

Now we can rewrite it as:

x^2 + y^2 -4x + 4y + 4 + 4 = 8\\\\x^2 + y^2 - 4x + 4y = 0

Remember that:

x^2 + y^2 = r^2\\\\x = r*cos(\theta)\\y = r*sin(\theta)

Replacing that, we get:

x^2 + y^2 - 4x + 4y = 0\\\\r^2 - 4r*cos(\theta) + 4r*sin(\theta) = 0

That is the equation in polar form.

Now, because we can discard the solution r = 0, we can divide both sides by r to get:

r - 4*cos(\theta) + 4*sin(\theta) = 0

To simplify it.

If you want to learn more about polar coordinates:

brainly.com/question/14965899

#SPJ1

4 0
2 years ago
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