I think the answer to this is: 25q + 10d + 5n + 60 = 87
The story says that you have 1 dollar and 87 cents; 60 cents
of which is pennies. So, if you’re using an equation involving quarters, dimes
and nickels, the total equation should equal to 87 cents (since that dollar
bill could not be broken down to cents).
Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P(
>
) = P(Z > 1.25) = 1 - P(Z
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Answer:
You add all them then divided 4 i think
Answer:
78,792,000,000,000 miles
Step-by-step explanation:
(5.88 * 10^12) * 13.4 = 78,792,000,000,000
Answer:
Step-by-step explanation:
<u>Given functions:</u>
- f (x) = 2x + 2
- g (x) = 3x – 1
<u>To find:</u>
<u>Solution</u>
- (f/g)(x) = f(x)/g(x) = (2x + 2) / (3x - 1)
- (f/g)(2) = (2*2 + 2) / (3*2 - 1) = 6/5 = 1.2