[Calc 1] An explanation on how to best solve this. I've been stuck trying to use chain rule
1 answer:
Answer:
G'(y) = 4y^7(y+4)/(y+2)^5
Step-by-step explanation:
Work it a piece at a time.
Define z = y^2/(y+2). Then your derivative is found from the power rule as ...
G = z^4
G' = 4z^3·z'
Now, define z = u/v. Then your derivative is found using the quotient rule:
z' = (vu' -uv')/v^2 = ((y+2)(2y) -(y^2)(1))/(y+2)^2
Putting this together we have ...
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ANSWER
A.
EXPLANATION
The given equation is
This equation is already in the form:
This is called the slope-intercept form.
The slope is
and the y-intercept is 3.
The correct answer is A.
In a situation where the line is not given in the slope intercept form, then you must rewrite in this form before comparing.
Answer:
Thus we find that velocity vector at time t is
(5t+15, 5t^2/2, 4t^2)
Step-by-step explanation:
given that acceleration vector is a funciton of time and at time t
v(t) can be obtained by integrating a(t)
v(t) =
Thus we use the fact that acceleration is derivative of velocity and velocity is antiderivative of acceleration.
The arbitary constant normally used for integration C is here C vector = initial velocity (u0,v0,w0)
Position vector can be obtained by integrating v(t)
Thus we find that velocity vector at time t is
(5t+15, 5t^2/2, 4t^2)