[Calc 1] An explanation on how to best solve this. I've been stuck trying to use chain rule
1 answer:
Answer:
G'(y) = 4y^7(y+4)/(y+2)^5
Step-by-step explanation:
Work it a piece at a time.
Define z = y^2/(y+2). Then your derivative is found from the power rule as ...
G = z^4
G' = 4z^3·z'
Now, define z = u/v. Then your derivative is found using the quotient rule:
z' = (vu' -uv')/v^2 = ((y+2)(2y) -(y^2)(1))/(y+2)^2
Putting this together we have ...
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Answer:
The correct option is D) (5x − 2)(2x − 3).
Step-by-step explanation:
Consider the provided expression.
Where x is time in minutes.
We need to find the appropriate form of the expression that would reveal the time in minutes when the trough is empty.
When the trough is empty the whole expression becomes equal to 0.
Substitute the whole expression equal to 0 and solve for x that will gives us the required expression.
Now consider the provided option.
By comparison the required expression is D) (5x − 2)(2x − 3).
Hence, the correct option is D) (5x − 2)(2x − 3).