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Karolina [17]
2 years ago
13

[Calc 1] An explanation on how to best solve this. I've been stuck trying to use chain rule

Mathematics
1 answer:
aev [14]2 years ago
4 0

Answer:

  G'(y) = 4y^7(y+4)/(y+2)^5

Step-by-step explanation:

Work it a piece at a time.

Define z = y^2/(y+2). Then your derivative is found from the power rule as ...

  G = z^4

  G' = 4z^3·z'

Now, define z = u/v. Then your derivative is found using the quotient rule:

  z' = (vu' -uv')/v^2 = ((y+2)(2y) -(y^2)(1))/(y+2)^2

Putting this together we have ...

  G'(y)=4\left(\dfrac{y^2}{y+2}\right)^3\cdot\dfrac{y^2+4y}{(y+2)^2}\\\\\boxed{G'(y)=\dfrac{4y^8+16y^7}{(y+2)^5}}

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The expression below shows the population of foxes in a forest after 12x years.
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6 0
3 years ago
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A basket had 120 star apples and mangoes.if there are 90 mangoes what is the ratio of mangoes to star apples.?
leva [86]

Answer:

3 : 1

Step-by-step explanation:

120-90=30

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3 years ago
What is the Pythagorean Theorem used for? What is the formula
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3 years ago
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Simplify this expression 10b+7-3b-2
iren2701 [21]

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7b+5

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3 years ago
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Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4%
bogdanovich [222]

Mr. Jackson invested $800 at 6% per year and $ 2400  at 4 % per year

<h3><u>Solution:</u></h3>

Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4% per year.

Let the sum invested be ‘a’ and ‘3a’ at 6% per year and 4 % per year respectively

Also, his annual return totaled $144

We can form following equation on the basis of question:-

\begin{array}{l}{\text { Then, } \frac{a \times 6 \times 1}{100}+\frac{3 a \times 4 \times 1}{100}=\$ 144} \\\\ {\frac{6 a}{100}+\frac{12 a}{100}=144} \\\\ {\frac{6 a+12 a}{100}=144} \\\\ {\frac{18 a}{100}=144} \\\\ {18 a=14400} \\\\ {a=14400 \div 18}\end{array}

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So, the amount of money invested at 6% is $800 and the amount of money invested at 4% is $ 2400

4 0
3 years ago
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