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galben [10]
4 years ago
12

You are trying to make a 10-digit license plate using only numbers. assuming no numbers can repeat, how would factorial notation

help you calculate the total number of license plates that can be made?
Mathematics
1 answer:
Wewaii [24]4 years ago
7 0

10\cdot9\cdot\ldots\cdot 2\cdot1=10!=3628800

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Please please help me!!
Gnom [1K]

Answer:

infinite solution

Step-by-step explanation:

if substitute 3y+4 Into 3x your equation should be 3(3y+4)-9=12 then you multiply and combine like terms then your answer should be 12=12 which is a true statement meaning it has infinite solutions

3 0
3 years ago
A flying disc has a radius of 10 inches what is the area of one side of the flying disc
gulaghasi [49]

Answer

D) 314 square inches

The area of the one side of the flying disc = 314 square inches

Step by step explanation

The radius of the flying disc = 10 inches

The disc is in circle shape.

Area of a circle = πr^2

The area of the flying disc = 3.14 * 10^2          [π = 3.14]

= 3.14 *100

= 314 square inches

The area of the one side of the flying disc = 314 square inches

Thank you.

7 0
3 years ago
Cual es la diferencia común de la secuencia aritmética 5,8,11,14?
loris [4]

Answer:

a

Step-by-step explanation:

8 0
3 years ago
Andre says that 5 3/4 + 2 1/4 = 7 1/2 because 7 4/8 = 7 1/2. Identify his mistake. Draw a picture to prove that he is wrong.
MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

The given expression is

5\frac{3}{4}+2\frac{1}{4} =7\frac{4}{8}=7\frac{1}{2}

We will rewrite the expression

\frac{23}{4}+\frac{9}{4} =\frac{60}{8}=7\frac{1}{2}

When we add the fraction

\frac{23+9}{4} = \frac{32}{4} = 8

While Andre says the answer is 7\frac{1}{2}

because Andre added the denominator where he has to make a common denominator that should be 4 instead of 8.

Andre made mistake in this step

Picture is given below :

3 0
4 years ago
Two isosceles triangles share the same base. Prove that the medians to this base are collinear. (There are two cases in this pro
Anna71 [15]

Answer:

Given: Two Isosceles triangle ABC and Δ PBC having same base BC. AD is the median of Δ ABC and PD is the median of Δ PBC.

To prove: Point A,D,P are collinear.

Proof:

→Case 1.  When vertices A and P are opposite side of Base BC.

In Δ ABD and Δ ACD

AB= AC   [Given]

AD is common.

BD=DC  [median of a triangle divides the side in two equal parts]

Δ ABD ≅Δ ACD [SSS]

∠1=∠2 [CPCT].........................(1)

Similarly, Δ PBD ≅ Δ PCD [By SSS]

 ∠ 3 = ∠4 [CPCT].................(2)

But,  ∠1+∠2+ ∠ 3 + ∠4 =360° [At a point angle formed is 360°]

2 ∠2 + 2∠ 4=360° [using (1) and (2)]

∠2 + ∠ 4=180°

But ,∠2 and ∠ 4 forms a linear pair i.e Point D is common point of intersection of median AD and PD of ΔABC and ΔPBC respectively.

So, point A, D, P lies on a line.

CASE 2.

When ΔABC and ΔPBC lie on same side of Base BC.

In ΔPBD and ΔPCD

PB=PC[given]

PD is common.

BD =DC [Median of a triangle divides the side in two equal parts]

ΔPBD ≅ ΔPCD  [SSS]

∠PDB=∠PDC [CPCT]

Similarly, By proving ΔADB≅ΔADC we will get,  ∠ADB=∠ADC[CPCT]

As PD and AD are medians to same base BC of ΔPBC and ΔABC.

∴ P,A,D lie on a line i.e they are collinear.




3 0
3 years ago
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