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3 years ago

how do the graphs of f(x) = sin x and g(x) = sin2x+3 compare. Must make two selections of the following that apply.

Mathematics

2 answers:

ivolga24 [154]3 years ago

4 0

Answer:

C. and E.

Step-by-step explanation:

Elena L [17]3 years ago

3 0

Answer:

The correct options are:

g(x) is shifted three units higher than f(x).

g(x) has a period that is half the period of f(x).

Step-by-step explanation:

We have to compare the graphs of the function:

$f(x)=\sin x$

and $g(x)=\sin 2x+3$

We have to select the correct options among the following:

As we know that the period of sine function is 2π.

i.e. Period of function f(x) is: 2π.

The period of sin(2 x) is π.

Hence, the period of the function g(x) function is π.

Hence, the period of g(x) is half the period of f(x).

Also we could observe that g(x) is shifted 3 units upward.

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Please help me , idk the answer

solmaris [256]

Hello!

The answer is 20.

On the left side of the table, you are counting by 1's so of course its going to be 0,1,2,3. Now, on the right side of the table, you are counting by 5's so its going to be 5,10,15,20.

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3 years ago

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yKpoI14uk [10]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please solve this question!!

GaryK [48]

Answer: (i) 1/221 (ii) 11/221 (iii) 95/663 (iv) 1/663

Step-by-step explanation:

(i) A deck of cards contains 4 Kings out of 52 total cards

1st draw: 4 Kings out of 52 total cards → 4/52 = 1/13

2nd draw: 3 remaining Kings out of 51 total remaining cards → 3/51 = 1/17

1st Draw 2nd Draw Outcome Probability

King: P(K) = 1/13 King: P(K₂/K₁) = 1/17 King, King (1/13) x (1/17) = 1/221

*************************************************************************************************

(ii) A deck of cards contains 4 Jacks, 4 Queens, & 4 Kings out of 52 total cards

1st draw: 12 Face cards out of 52 total cards → 12/52 = 3/13

2nd draw: 11 remaining Face cards out of 51 total remaining cards → 11/51

1st Draw 2nd Draw Outcome Probability

Face: P(F) = 3/13 Face: P(F₂/F₁) = 11/51 Face,Face (3/13) x (11/51) = 11/221

*************************************************************************************************

(iiI) A deck of cards contains 26 black cards out of 52 total cards but there are 2 black Jacks, 2 black Queens, and 2 black Kings.

1st draw: 20 Black (not Face) cards out of 52 total cards → 20/52 = 5/13

2nd draw: 19 remaining Black (not Face) cards out of 51 total remaining cards → 19/51

1st Draw 2nd Draw Outcome Probability

Black: P(B~) = 5/13 Black: P(B~₂/B~₁) = 19/51 B~,B~ (5/13) x (19/51) = 95/663

*************************************************************************************************

(ii) A deck of cards contains 4 Aces out of 52 total cards

1st draw: 4 Aces out of 52 total cards → 4/52 = 1/13

2nd draw: 1 Queen of Hearts out of 51 total remaining cards → 1/51

1st Draw 2nd Draw Outcome Probability

Ace: P(A) = 1/13 Qh: P(Qh₂/A₁) = 1/51 Ace,Queen(h) (1/13) x (1/51) = 1/663

7 0

4 years ago

Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 100 disks are sum

IrinaK [193]

Answer:

0.84

Step-by-step explanation:

Given that Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 100 disks are summarized as follows:

P(A) = 0.86, P(B) = 0.79, P(A') = 0.14, P(AUB) = 0.95

We are to find out P(A'UB)

We have

$P(AUB) =P(A)+P(B)-P(A\bigcap B)\\0.95=0.86+0.79-P(A\bigcap B)\\P(A\bigcap B)=0.70$

$P(A'UB) = P(A')+P(B)-P(A' \bigcap B)\\= 1-P(A) +P(B)-[P(B)-P(A \bigcap B)]\\= 1-0.86+0.79-P(B)+[tex]P(A'UB)=0.14+0.79-0.79+0.70\\=0.84$ P(A \bigcap B)[/tex]

7 0

3 years ago

Can somebody help me?

pashok25 [27]

The answer is B becuase if u take the reciplericle by the antiretroviral you would get B

3 0

3 years ago