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3 years ago

2.Solve the system using substitution.

1 answer:

3 0

2x+2y=38
y=x+3

First you would substitute the y for x+3
2x+2(x+3)=38

You would multiply the 2 by the x+3
2x+2x+6=38

Add the 2x and the 2x
4x+6=38

Subtract the 6 on both sides
4x=32

Divide the 4 on both sides
x=8

Now substitute the x in the second problum for 8
y=8+3

Add the 8 and the 3 to solve for y
y=11

Your answers
x=8
y=11
the correct answer would be A:(8,11)

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Greeley [361]

Answer:

Refer to attached

Step-by-step explanation:

The answer is attached and provided below

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4 0

3 years ago

In a class of P students, the average of test scores is 70. In another class the average test scores is 92. When scores of the t

Basile [38]

So, since averages are defined as:

$\frac{\sum_{k=1}^{P} P_k}{P}=70$

So, since P are the total number of elements and P_k is the P_kth student. This is saying if we sum over each student's score and divide it by the number of students, we should get P, which is true.

So, using that logic, the other class can be represented as:

$\frac{\sum_{k=1}^{N} N_k}{N}=70$

We can take both of these equations and multiply them by N:

$\sum_{k=1}^{P} P_k=70P$

$\sum_{k=1}^N N_k=92N$

So, if we want to find the average of this we should add both our equations then divide by P+N, which is the number of all the students.

$\frac{\sum_{k=1}^{P} P_k+\sum_{k=1}^{N}N_k}{N+P}=\frac{70P+92N}{N+P}$

To make this simpler we can replace our LHS with 86, since that's the average of both classes combined.

$86=\frac{92N+70P}{N+P} \implies\\ 86N+86P=92N+70P \implies \\ 16P=6N \implies \\ \frac{16P}{N}=6 \implies \\ \frac{P}{N}=\frac{6}{16}$

Simplified we would have P/N=3/8.

7 0

4 years ago

X + y = 5 y = 3x + 1 How do I find the solution from these two equations by graphing

Mandarinka [93]

Answer:

x=1, y=4

Step-by-step explanation:

x+y=5 - (1)

y=3x + 1 (2)

Sub (2) into (1)

x + (3x +1)=5

4x=5-1

x=4 ÷4

Sub x=1 into (2)

y=3(1)+1

= 4

5 0

3 years ago

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The diameter of a cylindrical water tank is 10ft and its height is 11 ft what's the volume of the tank used value 3.14and round

MakcuM [25]

Answer:

863.5 ft³

Step-by-step explanation:

Given that :

Diameter, d = 10 ft

Height, h = 11 feets

Radius of tank, r = d/ 2 = 10ft / 2 = 5 ft

The volume of a cylinder is calculated using the relation :

Volume = πr²h

Volume = 3.14 * 5^2 * 11

Volume = 3.14 * 25 * 11

Volume = 863.5ft³

7 0

3 years ago

-50 POINTS- please help

e-lub [12.9K]

Answer:

-13

-10

Step-by-step explanation:

A x = B

To find X

A ^ -1 A x = A ^ -1 B

x = A^ -1 B

x = -3/2 -5/2 2

-1 -2 4

Across times down

-3/2 * 2 + -5/2 *4 = -13

-1 *2 -2 * 4 = -10

The matrix is

-13

-10

7 0

4 years ago

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