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s2008m [1.1K]
3 years ago
10

PLEASE URGENT I DONT WANNA FAIL

Mathematics
1 answer:
oee [108]3 years ago
6 0

Answer:

She has not plotted it correctly.

Step-by-step explanation:

Point A’ should be at (0,2)

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{c(1) = 3/16<br> {c(n)=c(n−1)⋅4<br> ​ <br><br> what is the 3rd term in this sequence?
mote1985 [20]

Answer:

\large\boxed{c(3)=3}

Step-by-step explanation:

\left\{\begin{array}{ccc}c(1)=\dfrac{3}{16}\\\\c(n)=c(n-1)\cdot 4\end{array}\right

Put n = 2 and next n = 3 to the recursive formula:

c(2)=c(2-1)\cdot4=c(1)\cdot4\to c(2)=\dfrac{3}{16}\cdot4=\dfrac{3}{4}\\\\c(3)=c(3-1)\cdot4=c(2)\cdot4\to c(3)=\dfrac{3}{4}\cdot4=3

4 0
3 years ago
Figure TUVS is a parallelogram.
poizon [28]

Angles T and V of the parallelogram are equal to 91°.

Calculating the Value of x

In the parallelogram TUVS, adjacent angles U and V are given as,

U = 4x+9

V = 6x-29

Since U and V are adjacent angles, and as per the properties of a parallelogram, sum of adjacent angles is equal to 180°.

4x+9 + 6x-29 = 180

10x - 20 =180

10x = 200

x = 20

Calculating the Angles of the Parallelogram

∠U = 4x + 9

∠U = 4(20) + 9

∠U = 80 + 9

∠U = 89°

∠V = 6x - 29

∠V = 6(20) - 29

∠V = 120 - 29

∠V = 91°

According to the properties of a parallelogram, opposite angles are of equal measure.

∴ ∠T = ∠V and ∠S = ∠U

⇒ ∠T = 91° and ∠S = 89°

Learn more about a parallelogram here:

brainly.com/question/1563728

#SPJ1

5 0
2 years ago
Describe the scale of the graph
IRINA_888 [86]

Answer:

Step-by-step explanation:

You could talk about how how or low it goes.

For instance: if the graph was going very high then suddenly low you could say that it was going very high until it suddenly dropped.

HOPE I HELPED.

PLZ give me a brainiest

GOOD LUCK

8 0
3 years ago
Evaluate the expression below for s=5 and t=6 3st2 - s2
babunello [35]
170 is the answer to the question
6 0
3 years ago
The radius of a nitrogen atom is 5.8*10^-11 meters, and the radius of a beryllium atom is 1.12*10^-10 meters. Which atom has a l
Burka [1]
Nitrogen Radius = 5.8 x 10⁻¹¹ m

Beryllium Radius = 1.12 x 10⁻¹⁰ m

Let's find the quotient of N/Be :

(5.8x10⁻¹¹)/(1.12x10⁻¹⁰). But 10⁻¹¹/10⁻¹⁰ = 10⁽⁻¹¹⁺¹⁰⁾ = 10⁻¹ = 1/10 = 0.1

→ (5.8/1.12).(0.1) = 0.58/1.12 = 0.518.

Conclusion: the radius of Be is almost double than the radius of N
5 0
3 years ago
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