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3 years ago

10

PLEASE URGENT I DONT WANNA FAIL

1 answer:

oee [108]3 years ago

6 0

Answer:

She has not plotted it correctly.

Step-by-step explanation:

Point A’ should be at (0,2)

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Find the complex zeros of x^3+27. write f in factored form

aliina [53]

$x^3+27=0
\\x^3+3^3=0
\\(x+3)(x^2-3x+9)=0
\\x^2-3x+9=0
\\a=1,b=-3,c=9
\\
\\x_{1,2}= \frac{-b\pm \sqrt{b^2-4ac} }{2a} = \frac{-(-3)\pm \sqrt{(-3)^2-4\times1\times9} }{2\times1} =\frac{3\pm \sqrt{-27} }{2} =\frac{3\pm 3\sqrt{3}i }{2} 
\\
\\(x+3)(x-\frac{3+ 3\sqrt{3}i }{2})(x-\frac{3- 3\sqrt{3}i }{2})=0

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3 years ago

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guapka [62]

Answer:

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Step-by-step explanation:

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