Question

A line passes through point A(10,15). A second point on the line has an x-value that is 125% of the x-value of point A and a y-value that is 75% of the y-value of point A. Use point A to write an equation of the line in point-slope form.
An equation is y− = (x− )

Answer 1

The equation of the line in the point-slope form is y - 15 = $-\frac{3}{2}$ (x - 10)

Step-by-step explanation:

The point-slope form of a linear equation is $y-y_{1}=m(x-x_{1})$ , where

• m is the slope of the line, where $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ , $(x_{1},y_{1})$ and $(x_{2},y_{2})$ are two points on the line
• $(x_{1},y_{1})$ is a point on the line

∵ Point A = (10 , 15)

∵ The x-coordinate of the second point is 125% of x-coordinate

  of point A

∴ x-coordinate of second point = $\frac{125}{100}$ × 10

∴ x-coordinate of second point = 12.5

∵ The y-coordinate of the second point is 75% of y-coordinate

  of point A

∴ y-coordinate of second point = $\frac{75}{100}$ × 15

∴ y-coordinate of second point = 11.25

∴ The coordinates of the second point are (12.5 , 11.25)

Let us find the slope of the line by using the rule of it above

∵ $(x_{1},y_{1})$ = (10 , 15)

∵ $(x_{2},y_{2})$ = (12.5 , 11.25)

∴ $m=\frac{11.25-15}{12.5-10}=\frac{-3.75}{2.5}=-\frac{3}{2}$

Now we can write the equation

∵ The point-slope form is $y-y_{1}=m(x-x_{1})$

∵ $m=-\frac{3}{2}$

∵ $(x_{1},y_{1})$ = (10 , 15)

- Substitute these values in the form of the equation

∴ y - 15 = $-\frac{3}{2}$ (x - 10)

The equation of the line in the point-slope form is y - 15 = $-\frac{3}{2}$ (x - 10)

Learn more:

You can learn more about the linear equation in brainly.com/question/4152194

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