Question

A 12-sided die is rolled. The set of equally likely outcomes is {1,2,3,4,5,6,7,8,9,10,11,12). Find the probability of rolling a number greater than 12.
The probability of rolling a number greater than 12 is
(Type an integer or a simplified fraction.)

Answer 1

Answer:

$P(x>12) = 0$

Step-by-step explanation:

Given

$x = \{1,2,3,4,5,6,7,8,9,10,11,12\}$ --- outcomes

$n(x) = 12$ -- sample size

Required

$P(x > 12)$

This is calculated as:

$P(x > 12) = \frac{n(x > 12)}{n(x)}$

$n(x>12) = 0$ because none of the outcomes is greater than 12:

So:

$P(x > 12) =\frac{0}{12}$

$P(x>12) = 0$