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Rudiy27
3 years ago
5

To the nearest whole percent, what is the probability that a randomly chosen member of the JV swim team does not wear glasses an

d is in the 10th grade? 14% 17% 55% 67%

Mathematics
1 answer:
Yuri [45]3 years ago
4 0

Answer: 14%

Step-by-step explanation:

Complete question is provided in the attachment below:

Probability that members of the junior varsity swim team wear glasses = 55%=0.55

Given: P(wear glasses) = 0.55

P(not wear glasses) = 1-0.55 = 0.45

P(member in 10th grade | not wear glasses) = 30%

Using conditional probability formula:

P(B|A)=\dfrac{P(A\text{ and } B)}{P(A)}

\Rightarrow\ 0.30=\dfrac{P(\text{not wear glasses and in 10th grade})}{0.45}\\\\\Rightarrow\ P(\text{not wear glasses and in 10th grade})=0.45\times0.30\\\\0.135=13.5\%\approx14\%

Hence, the probability that a randomly chosen member of the JV swim team does not wear glasses and is in the 10th grade = 14%.

So, the correct option is "14%".

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Order the following numbers from least to greatest :
guapka [62]
You can choose to put all the numbers into decimals or fractions.
In this case, I will put the numbers all in decimals. 
We already have 2.07, -2.67, and 2.67 
2 \frac{7}{10} in a decimal is 2.7 because 7 is in the 'tenths' place and ten was our denominator
So all of our numbers are 2.7 2.01 2.67 and -2.67
Obviously a negative number will be last and you can line the other numbers to see which is the greatest
2.67
2.70 (if there is nothing there we can always put a zero)
2.01
So the first digit is all 2 so we look at the next digits which are 6, 7, and 0 
You should know how to order those numbers, so do the same here.
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7 0
4 years ago
Please help me with this please and thank you please actually help me please
iren2701 [21]

Answer:

The solution is (2, 2)

Step-by-step explanation:

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Hope this helps!

5 0
2 years ago
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adoni [48]
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4 years ago
A dentist is making identical dental care bags for patients using 56 tubes of toothpaste, 112 packets of floss, and 85 toothbrus
marin [14]

Answer : Greatest number of identical dental care bags the dentist can make with the least items leftover is 1.

Number of bags will be 2,4,3 respectively.

Explanation:

Number of tubes of toothpaste = 56

Number of packets of floss = 112

Number of toothbrushes = 85

So, Greatest number of identical dental care bags the dentist can make with the least amount of items leftover from toothbrush  = H.C.F of 56,112, 85=   1   ( ∵ as they are coprime to each other )

Since there is no common factor among 56,112,85 but there is common factor between 56 and 112 i.e. 56 remaining bags from toothbrushes will be 85-56=29 .

So we consider 28 ,

Now, 56 can be written as 28×2

112 can be written as  28×4 and

84 can be written as 28× 3

So, there can be 28 bags in which all the three materials can be present  and there is no leftover from toothpaste and floss but there is leftover from toothbrushes only as we consider 84 instead of 85 to get divisible by 28 so we get the common factor easily.

so, there will be 2 two bags for toothpastes and 4 bags for floss and 3 bags for toothbrushes.

8 0
3 years ago
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