All categories

3 years ago

What is the perimeter of this rectangle?

Mathematics

1 answer:

DochEvi [55]3 years ago

8 0

Step-by-step explanation:

The perimeter of a rectangle is 2(l+b)

l= x2-x1

b=y2-y1

2(l+b)=2(x2-x1+y2-y1)

You might be interested in

Solve 18n - 7p-15n = 5p for n.<br> A n = 1<br> B. n=2p<br> C. n = 1/2<br> D. n=4p

andrey2020 [161]

Answer:

<h3>The answer is option D</h3>

Step-by-step explanation:

18n - 7p-15n = 5p

To solve for n first make n the subject

Group like terms

That's

18n - 15n = 5p + 7p

Simplify

3n = 12p

Divide both sides by 3 to make n stand alone

That's

3n/3 = 12p/3

We have the final answer as

Hope this helps you

5 0

4 years ago

Read 2 more answers

Rectangle ABCD is similar to rectangle WXYZ. If the area of rectangle

mina [271]

Answer:

Step-by-step explanation:

the ratio = 24 ÷ 3 = 8

smaller area is $\frac{1536}{8^2}=24$

6 0

4 years ago

Y'all please help me! Basically just match up the points with an equation.

Len [333]

1. Y=-1/2x+1/2
2.Y=-2x-8
3.Y=-3/2x+2
4. Y=-4x-16
5.Y=-4/7x+2

4 0

3 years ago

Camila tiene 5 años más que un tercio de la edad de Luis. Si Luis tiene 33 años, ¿cuántos años tiene Camila?

UNO [17]

Answer:

Step-by-step explanation:

33/3=11

11+5=16

3 0

3 years ago

Read 2 more answers

Estion

dalvyx [7]

Using the Poisson distribution, it is found that there is a 0.507 = 50.7% probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

The parameters are:

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Considering the average of 15 birds every 2 hours during daylight hours, the mean for a 45-minute period is given by:

$\mu = 15 \times \frac{45}{120} = 5.625$

The probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours is given by:

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

In which:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.625}(5.625)^{0}}{(0)!} = 0.004$

$P(X = 1) = \frac{e^{-5.625}(5.625)^{1}}{(1)!} = 0.02$

$P(X = 2) = \frac{e^{-5.625}(5.625)^{2}}{(2)!} = 0.057$

$P(X = 3) = \frac{e^{-5.625}(5.625)^{3}}{(3)!} = 0.107$

$P(X = 4) = \frac{e^{-5.625}(5.625)^{4}}{(4)!} = 0.150$

$P(X = 5) = \frac{e^{-5.625}(5.625)^{5}}{(5)!} = 0.169$

Then:

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.004 + 0.02 + 0.057 + 0.107 + 0.15 + 0.169 = 0.507$

0.507 = 50.7% probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

3 0

2 years ago