Answer:
1/6
Step-by-step explanation:
The probability of <em>only</em> a heads on a coin is 1/2, and the probability of <em>only</em> a 3 on a die is 1/6. Multiply them together, and you get 1/6.
Answer:
x ∈ [-2, 7]
Step-by-step explanation:
The given equation ...
x^2 -5x -4 ≤ 10
can be rewritten as ...
x^2 -5x -14 ≤ 0
and factored as ...
(x +2)(x -7) ≤ 0
Clearly, the "or equal to" condition will be met when x=-2 and x=7. For values of x between these numbers, one factor is negative and the other is positive. Hence the product will be negative. So, numbers in that interval are the solution set.
x ∈ [-2, 7]
Answer:

Step-by-step explanation:
24 + 4y = 12y
- 4y - 4y
__________

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Answer: 56 degrees
Step-by-step explanation:
We know that angle between b and c is 90 degrees. Because there is a line dividing angles a and b from 124 and c, we also know that each side is 180 degrees (a and b add to 180, and 124 and c add to 180).
124 and c are supplementary angles. We can represent this in an equation to solve for c:

Answer:
AB = 16 Units
Step-by-step explanation:
In the given figure, CD is the diameter and AB is the chord of the circle.
Since, diameter of the circle bisects the chord at right angle.
Therefore, AE = 1/2 AB
Or AB = 2AE...(1)
Let the center of the circle be given by O. Join OA.
OA = OD = 10 (Radii of same circle)
Triangle OAE is right triangle.
Now, by Pythagoras theorem:
![OA^2 = AE^2 + OE^2 \\10^2 = AE^2 + 6^2 \\100= AE^2 + 36\\100-36 = AE^2 \\64= AE^2 \\AE = \sqrt{64}\\AE = 8 \\\because AB = 2AE..[From \: equation\: (1)] \\\therefore AB = 2\times 8\\\huge \purple {\boxed {AB = 16 \: Units}}](https://tex.z-dn.net/?f=%20OA%5E2%20%3D%20AE%5E2%20%2B%20OE%5E2%20%5C%5C%3C%2Fp%3E%3Cp%3E10%5E2%20%3D%20AE%5E2%20%2B%206%5E2%20%5C%5C%3C%2Fp%3E%3Cp%3E100%3D%20%20AE%5E2%20%2B%2036%5C%5C%3C%2Fp%3E%3Cp%3E100-36%20%3D%20AE%5E2%20%5C%5C%3C%2Fp%3E%3Cp%3E64%3D%20AE%5E2%20%5C%5C%3C%2Fp%3E%3Cp%3EAE%20%3D%20%5Csqrt%7B64%7D%5C%5C%3C%2Fp%3E%3Cp%3EAE%20%3D%208%20%5C%5C%3C%2Fp%3E%3Cp%3E%5Cbecause%20AB%20%3D%202AE..%5BFrom%20%5C%3A%20equation%5C%3A%20%281%29%5D%20%5C%5C%3C%2Fp%3E%3Cp%3E%5Ctherefore%20AB%20%3D%202%5Ctimes%208%5C%5C%3C%2Fp%3E%3Cp%3E%5Chuge%20%5Cpurple%20%7B%5Cboxed%20%7BAB%20%3D%2016%20%5C%3A%20Units%7D%7D%20)