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2 years ago

Mohon bantuannya kawan

Mathematics

1 answer:

Natasha_Volkova [10]2 years ago

8 0

Answer:

hope this helps you

God bless you

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Jace invested $8,300 in an account paying an interest rate of 6.6% compounded continuously. Assuming no deposits or withdrawals

kondor19780726 [428]

Answer:

$20911

Step-by-step explanation:

Given

Investment P₀ = $8300
Interest rate r = 6.6%
Compound = continuous
Time t=14 years
P = ?

Formula for continuous compound interest:

P = P₀e ^rt, where e = 2.71828, constant used for continuous interest
P = 8300*(2.71828)^(14*0.066)
P = $20910.57 = $20911 rounded to the nearest dollar

3 0

3 years ago

What is 2x566!!!!!!!!!!!

Effectus [21]

That would be 1,132

Please mark me brainliest.

8 0

3 years ago

Read 2 more answers

Consider A (-9, 4) and B (11, 17), find the coordinates for point P that partition A to B in a 3: 5 ratio.

Talja [164]

Answer:

C. (-1.5, 8.875)

Step-by-step explanation:

on a coordinate plane if point(x1,y1) and (x2,y2) is divided by a point p in ratio of m:n then coordinate of point p is given by

p = (nx1 + mx2/ m+n, ny1+my2/m+n)

_______________________________________________

Given point

A (-9, 4) and B (11, 17)

ratio 3:5

m:n = 3:5

m+n = 3+5 = 8

coordinate of point p that partition AB

x = (5*-9 + 3*11) / 5+3 y = (5*4 + 3*17) / 5+3

x = (-45 + 33) / 8 y = (20 + 51) / 8

x = (-12) / 8 y = (71) / 8

x = -3 / 2 = -1.5 y = 8.875

Thus, coordinate of point p is (-1.5, 8.875).

7 0

3 years ago

The red shape has been translated into the blue shape. The translation is

MAXImum [283]

Answer is (A). (X’ , Y’) = (x, y-6)

7 0

3 years ago

what is the equation of the line described below written in slope-intercept form? the line passing through point (2,2) and perpe

djverab [1.8K]

Answer:

The equation of line passing through point (2 , 2) and perpendicular to line y = x is y = - x + 4 .

Step-by-step explanation:

Given as :

The line equation is y = x

Now, equation of line in slope-intercept form y = m x + c

where m is the slope of line and c is y-intercept

Comparing given line equation with standard line equation

The slope of line y = x is m = 1

Again

Other line is passing through point (2 ,2) and is perpendicular to line y = x

Let The slope of other line = M

∵ From perpendicular lines property

Product of slope of lines = - 1

i.e m × M = - 1

Or , M = $\dfrac{ - 1}{m}$

Or, M = $\dfrac{ - 1}{1}$

∴ M = - 1

Now, Equation of other line in point-slope form

The other line is passing through point (2 , 2) and slope M = - 1

So, y - $y_1$ = M × (x - $x_1$ )

Or, y - 2 = - 1 × ( x - 2 )

Or, y - 2 = - x + 2

Or, y = - x + 2 + 2

Or, y = - x + 4

Hence, The equation of line passing through point (2 , 2) and perpendicular to line y = x is y = - x + 4 . Answer

5 0

4 years ago