<em><u>888 + 88 + 8 + 8 + 8 = 1000</u></em>
<em><u>have</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>nice</u></em><em><u> </u></em><em><u>day</u></em><em><u>!</u></em>
(6-3)÷3-6+2
3÷3-6+2
1-6+2
-5+2
-3
Answer:
Leg A = 3
Step-by-step explanation:
You use the equation A squared plus B squared equals C squared. Then, you substitute the value that you have, so the equation would be a squared plus 3 squared equals 5 squared. Next, you square the two values to make the equation a squared plus 16 equals 25. After that, you subtract one of the values (which in case is 16) on both that leg value and the hypotenuse, so you are left with A squared equals 9. Finally, you square both 9 and A squared and you are left with A = 3. I hope that helps you understand it clearly!
Answer:
the answer would be -18
Step-by-step explanation:
3+3=6 2×6=12. 7+3=10 3×10=30 12-30= -18
Answer:
Step-by-step explanation:
Comment
I find the wording a bit confusing. Does the question mean that the laws of algebra determine what single vale of x will make the right side = the left side in both equations?
I think that's the way I will interpret it.
The easiest way to solve both of them is to divide by 4 on both sides of the top equation and divide by 2 on the bottom equation.
Solution
Top equation
4(x - 2) = 1000 Divide by 4
4(x-2 )/ 4 = 1000/4
(x - 2) = 250 Remove the brackets
x - 2 = 250 Add 2 to both sides
x - 2 + 2 = 250 + 2 Combine
x = 252
Bottom equation
2(x - 2) = 50 Divide by 2
2(x - 2)/2 = 50/2
(x - 2) = 25 Remove the brackets
x - 2 = 25 Add 2 to both sides
x - 2 + 2 = 25 + 2 Combine
x = 27
Conclusion
If the equations are structured the same way but have different numbers then the answers will be unique.
