x=2 is only solution while x=1 is extraneous solution
Option C is correct.
Step-by-step explanation:
We need to solve the equation
and find values of x.
Solving:
Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)
Multiply the entire equation with x(x-1)

Now, factoring the term:

The values of x are x=1 and x=2
Checking for extraneous roots:
Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.
If we put x=1 in the equation,
the denominator becomes zero i.e
which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.
If we put x=2 in the equation,


So, x=2 is only solution while x=1 is extraneous solution
Option C is correct.
Keywords: Solving Equations and checking extraneous solution
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Answer:
It would be 2. 6x - 1 = 1 + x
Step-by-step explanation:
Answer:
p= 8
Step-by-step explanation:
just collect the like terms together
12+5-9= p
p= 8
Step-by-step explanation:
5m³ + 2m - 7m³ - 8m
= -2m³ -6m
= -2m(m² + 3)
Answer:
It's really easy just remember rise over run.
Step-by-step explanation:
so you rise 3 and run to the right 3
A great tip that helps me determine if it's positive or neagitve is if you go to the left then it's ALWAYS neagtive but if you go to the right then it's ALWAYS postive