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RoseWind [281]
2 years ago
14

Use the distributive property to factor the expression below. 5x2 + 25

Mathematics
1 answer:
ollegr [7]2 years ago
6 0
First you need to find the highest common factor of 5x² and 25, which is 5 because there is no x term in 25. This means that 5 goes on the outside of the brackets, like 5 (______). To get 5x² from 5, you need to multiply by x², which is your first term in the brackets. To get 25 from 5, you need to multiply by 5, which would be your second term, so your final answer is 5(x² + 5). I hope this helps!
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Can someone do 4,5,6,and 7 for me
Flauer [41]

Answer:

4.=11   5.=4  6.=17  7.=47    I think

Step-by-step explanation:

an absolute value of a number is never negative so you just make the number positive and go about the equation normally

6 0
3 years ago
Read 2 more answers
Write a definite integral that represents the area of the region. (Do not evaluate the integral.) y1 = x2 + 2x + 3 y2 = 2x + 12F
Svet_ta [14]

Answer:

A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36

Step-by-step explanation:

The equations are:

y = x^{2} + 2x + 3

y = 2x + 12

The two graphs intersect when:

x^{2} + 2x + 3 = 2x + 12

x^{2} = 0

x_{1}  = 3\\x_{2}  = -3

To find the area under the curve for the first equation:

A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx

To find the area under the curve for the second equation:

A_{2} = \int\limits^3__-3}{2x + 12} \, dx

To find the total area:

A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx

Simplifying the equation:

A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).  

3 0
2 years ago
What are 3 input and output values for the equation y=-x^2+4?
pogonyaev
Here, The function:  y = -x² + 4
Input values would be x coordinates & output values would be y.

When, x = 1, y = (-1)² + 4 = 1 + 4 = 5
x = 2, y = (-2)² + 4 = 4 + 4 = 8
x = 3, y = (-3)² + 4 = 9 + 4 = 13

In short, Your Three input values are: 1, 2, 3
Three Output values are: 5, 8, 13

Hope this helps!
4 0
2 years ago
Name two pairs of supplementary angles in the diagram.
Ipatiy [6.2K]

Answer:

Step-by-step explanation:

α + β = 180°

∠BFE and ∠FBC

∠CEF and ∠BCE

6 0
3 years ago
A math test is worth 100 points and has 38 problems. Each problem is worth either 5 points or 2 points. How many problems of eac
Nat2105 [25]

Answer:

<em><u>5</u></em><em><u> </u></em><em><u>points</u></em><em><u> </u></em><em><u>question</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>8</u></em>

<em><u>and</u></em><em><u> </u></em><em><u>2</u></em><em><u> </u></em><em><u>po</u></em><em><u>ints</u></em><em><u> questions</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>3</u></em><em><u>0</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em>

Step-by-step explanation:

Let the number of 5 points questions be x and number of the 2 points questions be y !!

Given :- The paper has 38 problems

i.e,

number of 5 points Q + number of 2point Q = 38

=> x + y = 38

=> x = 38 - y .... ( i )

And , The test worth 100 pts :-

There must be x number of Questions which carry 5 points and there must y number of questions which carries 2 points ( as assume above )

so, 5x + 2y = 100 .... ( ii )

Putting value of the x in ( ii )

5 ( 38 - y ) + 2y = 100

190 - 5y + 2y = 100

- 3y = - 90

y = 30

Putting value of y in ( i )

x = 38 - y

x = 38 - 30

x = 8

So, the Number of 5points Question is

x = 8

and , the number of 2 points questions is y = 30 !!

4 0
3 years ago
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