The standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
<h3>How to represent the
quadratic function in standard form?</h3>
The quadratic function is given as
f(x) = -3x^2 + 6x - 2
The standard form of a quadratic function is represented as:
f(x) = ax^2 + bx + c
When both equations are compared, we can see that the function f(x) = -3x^2 + 6x - 2 is already in standard form
Where
a = -3
b = 6
c = -2
Hence, the standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
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Answer: its 4
Step-by-step explanation: i took the quiz just now
Answer:
d
Step-by-step explanation:
sin angle (60) would have been equal to 0.5 or a 1/2
and cos angle(60) would have been equal to 0.86 then you'll say square by 3 over 2
Let me know if this answer can work
Best of Luck
Answer:

<h3>2x-9y=1 is the correct answer of this question..</h3>
Thank you ☺️☺️