Assuming your equation is: -2/5n = -30
-2/5n = -30 <- We get rid of the "/5n" by multiplying each side by 5n
-2 = -30 * 5n
-2 = -150n
-1 = -75n
75n = 1
But this doesn't match up with any of your answers, so if you wouldn't mind giving me the equation again, i'll work it out
Its 0.20 i think bc its the one that make the most since
You have $15 and admission is $5, so you know have $10 before doing any games. If you wanted to play 12 games, you would need $10.20, which you do not have. But, if you wanted to play 11 games, then you would need $9.35, which is just under $10.
So the maximum amount of games that you could play would be 11 games.
Answer:
x=3, y=0.8
Step-by-step explanation:
8x+5y=28
4x+5y=16
Subtract the second simultaneous equation from the first.
You are left with: 4x=12
12/4=3
x=3
Substitute this back into one of the equations.
8(3)+5y=28
8*3=24
28-24=4
4=5y
4/5=0.8
y=0.8
