Answer:
C. Up.
Step-by-step explanation:
We have been given that the parent function
is transformed to the function
. We are asked to describe the given transformation.
Let us recall the transformation rules.
,
,
,
.
Upon comparing our transformed function with the parent function, we can see that the graph is shifted to left by 7 units and upwards by 5 units.
Therefore the correct choice is option C.
![\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvertical%20parabola%20vertex%20form%20with%20focus%20point%20distance%7D%20%5C%5C%5C%5C%204p%28y-%20k%29%3D%28x-%20h%29%5E2%20%5Cqquad%20%5Cbegin%7Bcases%7D%20%5Cstackrel%7Bvertex%7D%7B%28h%2Ck%29%7D%5Cqquad%20%5Cstackrel%7Bfocus~point%7D%7B%28h%2Ck%2Bp%29%7D%5Cqquad%20%5Cstackrel%7Bdirectrix%7D%7By%3Dk-p%7D%5C%5C%5C%5C%20p%3D%5Ctextit%7Bdistance%20from%20vertex%20to%20%7D%5C%5C%20%5Cqquad%20%5Ctextit%7B%20focus%20or%20directrix%7D%5C%5C%5C%5C%20%5Cstackrel%7B%22p%22~is~negative%7D%7Bop%20ens~%5Ccap%7D%5Cqquad%20%5Cstackrel%7B%22p%22~is~positive%7D%7Bop%20ens~%5Ccup%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)

something noteworthy is that the squared variable is the "x", thus the parabola is a vertical one, the "p" value is negative, so is opening downwards, and the h,k is pretty much the origin,
vertex is at (0,0)
the focus point is "p" or 5 units down from there, namely at (0, -5)
the directrix is "p" units on the opposite direction, up, namely at y = 5
the focal width, well, |4p| is pretty much the focal width, in this case, is simply yeap, you guessed it, 20.
Add those equations together
<span>1. 4x = 16, x = 4
2. Multiple the second one by 2
2x+4y=22
4x-4y=-16
6x = 6, x = 1
3. Add them together
8x = 24, x = 3
</span>
Answer:
D(1, 2) → D'(2, 7)
E(-3, -5) → E'(-10, 0)
F(4, -1) → F'(11, 4)
Step-by-step explanation:
D(1, 2) → D' ________
Translate image (3x - 1, y + 5)
(1, 2), x = 1 and y = 2
3x - 1 = 3(1) - 1 = 3 - 1 = 2
y + 5 = (2) + 5 = 7
E(-3, -5) → E' ________
(-3, -5), x = -3 and y = -5
3x - 1 = 3(-3) - 1 = -9 - 1 = -10
y + 5 = (-5) + 5 = 0
F(4, -1) → F' ________
(4, -1), x = 4 and y = -1
3x - 1 = 3(4) - 1 = 12 - 1 = 11
y + 5 = (-1) + 5 = 4
8*4
I hope that helps !
So, 4*4*4*4 = 16+16 which is 32