Using a linear search to find a value that is stored in the last element of an array of 20,000 elements, 20,000 element(s) must be compared.
The gear ratios would look like A:B=1:9 and C:D=1:32 if you are just needing the gear teeth ratio. Not a lot of information to go off of from the question though
Answer:
Following is attached the code that works accordingly as required. It reads in characters from standard input and outputs the number of times it sees an 'a' followed by the letter 'b'. All the description of program is given inside the code as comments.
I hope it will help you!
Explanation:
Answer:
class PersonInfo:
def __init__(self):
self.num_kids = 0
def inc_num_kids(self):
self.num_kids += 1
person1 = PersonInfo()
print('Kids:', person1.num_kids)
person1.inc_num_kids()
print('New baby, kids now:', person1.num_kids)
Explanation:
Line 1 of the code, we define the class PersonInfo. Line 3 of the code is the function that will increment the member data num_kids.
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